一道尚未评定的水题 更好的阅读体验 思路 来分析分析样例: 3 -5 10 5 我们把它升序排列,会得到这个东西↑ 不仔细地观察后可以发现:加一个(0,0)的点显然是最优的 再用脚趾头想想为什么,我们发现,这题题意就是想让我们把一段线段x等分,使得给出的点都是它的x等分点. 而通过我们的敏锐的第六感做题经验,不难看出最优解即相邻点距离的最大公约数 做法 显然此题难点在于求n个数的gcd 而要求多个数的gcd,两两求之后合并即可. 证明: 以三个数为例,设有a,b,c三数,x=gcd(a,b),y…

一.在using_marker/src中编写点和线代码 vim ~/catkin_ws/src/using_marker/src/points_and_lines.cpp 编写代码,其中有注释 #include <ros/ros.h> #include <visualization_msgs/Marker.h> #include <cmath> int main( int argc, char** argv ) { //创建一个发布器 ros::init(argc, a…

给定二维平面上有 n 个点,求最多有多少点在同一条直线上. 详见:https://leetcode.com/problems/max-points-on-a-line/description/ Java实现: /** * Definition for a point. * class Point { * int x; * int y; * Point() { x = 0; y = 0; } * Point(int a, int b) { x = a; y = b; } * } */ class…

Visulalize Boost Voronoi in OpenSceneGraph eryar@163.com Abstract. One of the important features of the boost polygon library is the implementation of the generic sweepline algorithm to construct Voronoi diagrams of points and linear segments in 2D(d…

截至UE4  4.10 runtime 无法生成BSP类 ,只能通过自定义的Mesh的Vertex 进行绘制 ( Google 考证,能改UE4源码的请忽略 ) 可用到的 UE4 集成的Render Plugins : CustomMeshComponent ProceduralMeshComponent 以下是参考 参考文献: https://wiki.unrealengine.com/Procedural_Mesh_Generation https://answers.unrealengin…

Nice R Code Punning code better since 2013 RSS Blog Archives Guides Modules About Markov Chain Monte Carlo 10 JUNE 2013 This topic doesn’t have much to do with nicer code, but there is probably some overlap in interest. However, some of the topics th…

前言 公司开展一个项目,需要根据客户手机定位获取周围内的精准广告,具体是管理员在地图上绘制多边形的广告范围,落在范围内的客户就看到此广告.下面将我的实现方法简单叙述一下,以供有相同需求的朋友参考. EF平面对象DbGeometry DbGeometry可以表示点.线.多边形等平面对象,输入对象可以是WKT(Well-known text),我们可以把百度地图上的polygon对象的点转换为多边形的wkt描述,再转为DbGeometry进行保存. /// <summary> /// 从多点数据生…

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'''---------------------------------------------------------------------------------- Tool Name: CreateFeaturesFromTextFile Source Name: CreateFeaturesFromTextFile.py Version: ArcGIS 9.1 Author: Environmental Systems Research Institute Inc. Required…

import java.util.ArrayList; import java.util.Scanner; public class Solution { public static void main(String[] args) { ArrayList<String> list = new ArrayList<>(); Scanner input = new Scanner(System.in); System.out.print("Enter the count o…