简单的母函数应用. #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<string> #include<cmath> #include<map> #include<set> #include<vector> #include<algorithm> #include<sta…
Holding Bin-Laden Captive! Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 17653    Accepted Submission(s): 7902 Problem Description We all know that Bin-Laden is a notorious terrorist, and he h…
Description We all know that Bin-Laden is a notorious terrorist, and he has disappeared for a long time. But recently, it is reported that he hides in Hang Zhou of China! “Oh, God! How terrible! ” Don’t be so afraid, guys. Although he hides in a cave…
//给你面值为1,2,5的三种硬币固定的数目,求不能凑出的最小钱数 //G(x)=(1+x+...+x^num1)(1+x^2+...+x^2num2)(1+x^5+,,,+x^5num3), //展开,系数不为0的数都是能够由硬币组合出来的. # include <algorithm> # include <string.h> # include <stdio.h> # include <iostream> using namespace std; int…
题目:http://acm.hdu.edu.cn/showproblem.php?pid=1085 可以这样理解题意:给出1元,2元和5元的三种硬币若干,每种硬币数量给出,现在可以从所有的硬币中,选出若干(三种中的若干种,若干个)组合出一定的金额,待求的是不能组合出来的金额的最小值. 例如 题目给出的测试例题中,三种硬币数量分别为1,1,3,则题目抽象成数学问题为: (1+x)(1+x^2)(1+x^5+x^10+x^15)的乘积展开式中,按照次数递增的顺序排列,第一个系数为0的项的次数是多少次…
列出生成函数的多项式之后暴力乘即可 #include<iostream> #include<cstdio> #include<cstring> using namespace std; const int N=20005; int n,x,y,z,a[N],b[N]; int main() { while(scanf("%d%d%d",&x,&y,&z)&&x+y+z) { memset(a,0,sizeof(…
1.TreeMap和TreeSet类:A - Language of FatMouse ZOJ1109B - For Fans of Statistics URAL 1613 C - Hardwood Species POJ 2418D - StationE - Web Navigation ZOJ 1061F - Argus ZOJ 2212G - Plug-in2.SegmentTreeA-敌兵布阵 hdu 1166B - I Hate It HDU 1754C - A Simple Pro…
杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…
转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…
[译文] 摘要:为一个简单的有漏洞程序写一个简单的缓冲区溢出EXP,聚焦于遇到的问题和关键性的教训,提供详细而彻底的描述 内容表:1. I pity the fool, who can't smash the stack:--介绍&背景2.Welcome to the jungle, we've got fun and wargames:--介绍我们之后要使用的示例&分析它的源代码3. There is no spoon. This causes problems when you try…