ZOJ 3555 Ice Climber(dp)

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ZOJ 3555 Ice Climber(dp)

晦涩的题意+各种傻逼害我调了那么久,实际上题目就是一个dp[i][j],dp[i][j]表示第i层第j个最少需要多少时间,当我们去更新dp[i][j]的时候,考虑的是从第i+1层的某一个dp[i+1][k]往上顶一层,然后走到dp[i][j]的位置,当然往上跳的时候要注意不要碰到怪物墙壁,各种坑,我的码力果然不行呀- -0 #pragma warning(disable:4996) #include<iostream> #include<cstdio> #include<cs…

ZOJ3555 Ice Climber(dp)

转载请注明出处: http://www.cnblogs.com/fraud/ ——by fraud Ice Climber Time Limit: 2 Seconds Memory Limit: 32768 KB Maybe many one have played or at least heard of The Family Computer(FC). And this problem is mainly about a classical game named …

Bomb HDU - 3555 （数位DP）

Bomb HDU - 3555 (数位DP) The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the time bomb. The number sequence of the time bomb counts from 1 to N. If the current number sequence includes the sub-sequence "49&…

ZOJ Problem Set - 3822Domination(DP)

ZOJ Problem Set - 3822Domination(DP) problemCode=3822">题目链接题目大意: 给你一个n * m的棋盘,每天都在棋盘上面放一颗棋子.直到这个棋盘上的每行每列都有至少有一颗棋子.求要用的天数的期望. 解题思路: 先求出不同摆法的棋盘的概率,然后在和天数相乘就是期望. 我们将棋盘划分为四个部分:当中一部分为每行没列都至少有一个棋子. 然后得出状态转移方程: dp[x][y][k…

HDU(3555)，数位DP

题目链接:http://acm.split.hdu.edu.cn/showproblem.php?pid=3555 Bomb Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others)Total Submission(s): 15372 Accepted Submission(s): 5563 Problem Description The counter-terrorists f…

HDU 3555 Bomb 数位dp

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=3555 Bomb Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/65536 K (Java/Others) 问题描述 The counter-terrorists found a time bomb in the dust. But this time the terrorists improve on the time bo…

zoj 3537 Cake 区间DP （好题）

题意:切一个凸边行,如果不是凸包直接输出.然后输出最小代价的切割费用,把凸包都切割成三角形. 先判断是否是凸包,然后用三角形优化. dp[i][j]=min(dp[i][j],dp[i][k]+dp[k][j]+w[i][k]+w[j][k]); w[i][j]代表i到j点的切割费用. dp[i][j]:表示以i到j点的最小费用.则可把凸边行分成三个部分的费用.两个凸边行(i,k),(k,j)和两条边的费用(i,k),(j,k),k为枚举的三角形顶点. Zoj 3537 Cake (DP_最优三…