poj 3684】的更多相关文章

Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 784   Accepted: 266   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment, a…
Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 2936   Accepted: 1045   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment,…
Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 1489   Accepted: 509   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment,…
原题如下: Physics Experiment Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 3583   Accepted: 1275   Special Judge Description Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the exper…
Description Simon ), the first ball is released and falls down due to the gravity. After that, the balls are released one by one in every second until all balls have been released. When a ball hits the ground, it will bounce back with the same speed…
强连通算法推断是否满足2-sat,然后反向建图,拓扑排序+染色. 一种选择是从 起点開始,还有一种是终点-持续时间那个点 開始. 若2个婚礼的某2种时间线段相交,则有矛盾,建边. easy出错的地方就在于推断线段相交. 若s1<e2&&s2<e1则相交 输出路径的做法能够參考论文2-SAT解法浅析 #include <iostream> #include<cstring> #include<cstdio> #include<string…
和蚂蚁问题类似. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; int c,n; double h,r,t,T; ]; double cal(double time) { ) return h; ; ) { if(time<=T…
Simon is doing a physics experiment with N identical balls with the same radius of R centimeters. Before the experiment, all N balls are fastened within a vertical tube one by one and the lowest point of the lowest ball is H meters above the ground.…
POJ 1852 Ants POJ 2386 Lake Counting POJ 1979 Red and Black AOJ 0118 Property Distribution AOJ 0333 Ball POJ 3009 Curling 2.0 AOJ 0558 Cheese POJ 3669 Meteor Shower AOJ 0121 Seven Puzzle POJ 2718 Smallest Difference POJ 3187 Backward Digit Sums POJ 3…
poj 1852 3684 这两题思路相似就放在一起. 1852 题意 一块长为L长度单位的板子(从0开始)上有很多只蚂蚁,给出它们的位置,它们的方向不确定,速度为每秒一长度单位,当两只蚂蚁相遇的时候,它们会反向而行,问所有蚂蚁到达终点(到0或者到L)所需要的最短时间和最长时间. 解析 一开始拿到这题觉得还是有点难度的,但一想通就发现这是个大水题.我们可以假设两只蚂蚁它们相向而行,并且它们中间没有别的蚂蚁,此时它们距离为k,经过时间t后它们相遇,此时它们反向,又经过时间t它们再次之间距离还是k.…
POJ 排序的思想就是根据选取范围的题目的totalSubmittedNumber和totalAcceptedNumber计算一个avgAcceptRate. 每一道题都有一个value,value = acceptedNumber / avgAcceptRate + submittedNumber. 这里用到avgAcceptedRate的原因是考虑到通过的数量站的权重可能比提交的数量占更大的权重,所以给acceptedNumber乘上了一个因子. 当然计算value还有别的方法,比如POJ上…
Halloween treats Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 7644   Accepted: 2798   Special Judge Description Every year there is the same problem at Halloween: Each neighbour is only willing to give a certain total number of sweets…
Find a multiple Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7192   Accepted: 3138   Special Judge Description The input contains N natural (i.e. positive integer) numbers ( N <= 10000 ). Each of that numbers is not greater than 15000…
The Pilots Brothers' refrigerator Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 22286   Accepted: 8603   Special Judge Description The game “The Pilots Brothers: following the stripy elephant” has a quest where a player needs to open a…
Flip Game Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 37427   Accepted: 16288 Description Flip game is played on a rectangular 4x4 field with two-sided pieces placed on each of its 16 squares. One side of each piece is white and the…
Corn Fields Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 9806   Accepted: 5185 Description Farmer John has purchased a lush new rectangular pasture composed of M by N (1 ≤ M ≤ 12; 1 ≤ N ≤ 12) square parcels. He wants to grow some yumm…
Sum of Consecutive Prime Numbers Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 20050   Accepted: 10989 Description Some positive integers can be represented by a sum of one or more consecutive prime numbers. How many such representatio…
Tree Recovery Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 11939   Accepted: 7493 Description Little Valentine liked playing with binary trees very much. Her favorite game was constructing randomly looking binary trees with capital le…
Seek the Name, Seek the Fame Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 17898   Accepted: 9197 Description The little cat is so famous, that many couples tramp over hill and dale to Byteland, and asked the little cat to give names t…
题目: poj 2352 Stars 数星星 题意:已知n个星星的坐标.每个星星都有一个等级,数值等于坐标系内纵坐标和横坐标皆不大于它的星星的个数.星星的坐标按照纵坐标从小到大的顺序给出,纵坐标相同时则按照横坐标从小到大输出. (0 <= x, y <= 32000) 要求输出等级0到n-1之间各等级的星星个数. 分析: 这道题不难想到n平方的算法,即从纵坐标最小的开始搜,每次找它前面横坐标的值比它小的点的个数,两个for循环搞定,但是会超时. 所以需要用一些数据结构去优化,主要是优化找 横坐…
poj   1251  Jungle Roads  (最小生成树) Link: http://poj.org/problem?id=1251 Jungle Roads Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 23507   Accepted: 11012 Description The Head Elder of the tropical island of Lagrishan has a problem. A b…
Kaka's Matrix Travels Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 9567   Accepted: 3888 Description On an N × N chessboard with a non-negative number in each grid, Kaka starts his matrix travels with SUM = 0. For each travel, Kaka mo…
Friendship Time Limit: 2000MS   Memory Limit: 20000K Total Submissions: 10626   Accepted: 2949 Description In modern society, each person has his own friends. Since all the people are very busy, they communicate with each other only by phone. You can…
Ikki's Story I - Road Reconstruction Time Limit: 2000MS   Memory Limit: 131072K Total Submissions: 7659   Accepted: 2215 Description Ikki is the king of a small country – Phoenix, Phoenix is so small that there is only one city that is responsible fo…
http://poj.org/problem?id=1144 题意:给你一些点,某些点直接有边,并且是无向边,求有多少个点是割点 割点:就是在图中,去掉一个点,无向图会构成多个子图,这就是割点 Tarjan算法求割点的办法 如果该点为根,那么它的子树必须要大于1 如果该点不为根,那么当low[v]>=dnf[u]时,为割点 Low[v]>=dnf[u]也就是说明U的子孙点只能通过U点访问U的祖先点 #include <stdio.h> #include <stack>…
http://poj.org/problem?id=3614 题意:有n头奶牛想要晒太阳,但他们每个人对太阳都有不同的耐受程度,也就是说,太阳不能太大也不能太小,现在有一种防晒霜,涂抹这个防晒霜可以把太阳的强度固定到一个值 求一共有多少头奶牛可以晒太阳 #include <stdio.h> #include <queue> #include <stdlib.h> using namespace std; int m,n; struct co{ int mi,ma; }c…
POJ 3669 去看流星雨,不料流星掉下来会砸毁上下左右中五个点.每个流星掉下的位置和时间都不同,求能否活命,如果能活命,最短的逃跑时间是多少? 思路:对流星雨排序,然后将地图的每个点的值设为该点最早被炸毁的时间 #include <iostream> #include <algorithm> #include <queue> #include <cstring> using namespace std; #define INDEX_MAX 512 int…
POJ 3009 题意: 给出一个w*h的地图,其中0代表空地,1代表障碍物,2代表起点,3代表终点,每次行动可以走多个方格,每次只能向附近一格不是障碍物的方向行动,直到碰到障碍物才停下来,此时障碍物也会随之消失,如果行动时超出方格的界限或行动次数超过了10则会game over .如果行动时经过3则会win,记下此时行动次数(不是行动的方格数),求最小的行动次数 #include<cstdio> #include<iostream> #include<cstring>…
更新中... http://poj.org/problem?id=1037 dp[i][j][0]表示序列长度为i,以j开始并且前两位下降的合法序列数目; dp[i][j][1]表示序列长度为i, 以j开始并且前两位上升的合法序列数目; 于是我们可以得到递推方程式:dp[i][j][0] += dp[i-1][k][1] ( 1 <= k < j ), dp[i][j][1] += dp[i-1][k][0] ( k <= j <= i), 然后我们就可以从第一位开始枚举了. ht…
SudoKu Time Limit:2000MS     Memory Limit:65536KB     64bit IO Format:%lld & %llu POJ 2676 Description Sudoku is a very simple task. A square table with 9 rows and 9 columns is divided to 9 smaller squares 3x3 as shown on the Figure. In some of the c…