Reverse a Singly LinkedList * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { * val = x; * next = null; * } * } */ 这是面试的时候被问到的一题,还是考察LinkedList的理解,最后如何得到reverse之后的head的. public Class Soluti…

Reverse a singly linked list. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 递归的办法: /** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { v…

Reverse a singly linked list. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseList(ListNode* head) { if (head == NUL…

Reverse a singly linked list  http://angelonotes.blogspot.tw/2011/08/reverse-singly-linked-list.html Source   1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 #include <stdio.h>   typedef st…

前段时间在看一本01年出的旧书<effective Tcp/Ip programming>,这个算法专题中断了几天,现在继续写下去. Introduction 对于单向链表(singly linked list),每个节点有⼀个next指针指向后一个节点,还有一个成员变量用以储存数值:对于双向链表(Doubly LinkedList),还有一个prev指针指向前一个节点.与数组类似,搜索链表需要O(n)的时间复杂度,但是链表不能通过常数时间读取第k个数据.链表的优势在于能够以较⾼的效率在任意位…

Reverse a singly linked list. click to show more hints. Hint: A linked list can be reversed either iteratively or recursively. Could you implement both? 之前做到Reverse Linked List II 倒置链表之二的时候我还纳闷怎么只有二没有一呢,原来真是忘了啊,现在才加上,这道题跟之前那道比起来简单不少,题目为了增加些许难度,让我们分别用…

#206.  Reverse Linked List Reverse a singly linked list. /** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ class Solution { public: ListNode* reverseList(ListNo…

Reverse a singly linked list. 这题因为palindrome linked list 的时候需要就顺便做了一下.利用三个指针:prev, now, next 相互倒腾就行. /** * Definition for singly-linked list. * function ListNode(val) { * this.val = val; * this.next = null; * } */ /** * @param {ListNode} head * @retu…

Reverse a singly linked list. 解题思路: 用Stack实现,JAVA实现如下: public ListNode reverseList(ListNode head) { if(head==null) return null; Stack<ListNode> stack =new Stack<ListNode>(); ListNode temp=head; while(temp!=null){ stack.push(temp); temp=temp.ne…

Reverse a singly linked list. 思路:没啥好说的.秒... ListNode* reverseList(ListNode* head) { ListNode * rList = NULL, * tmp = NULL; while(head != NULL) { tmp = rList; rList = head; head = head->next; rList->next = tmp; } return rList; }…