题目要求 You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels. The letters in …
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述: 题目大意 解题方法 数组count 字典Counter 日期 题目地址:https://leetcode.com/problems/jewels-and-stones/description/ 题目描述: You're given strings J representing the types of stones that are jewels, and S rep…
题目描述 给定字符串J 代表石头中宝石的类型,和字符串 S代表你拥有的石头. S 中每个字符代表了一种你拥有的石头的类型,你想知道你拥有的石头中有多少是宝石. J 中的字母不重复,J 和 S中的所有字符都是字母.字母区分大小写,因此"a"和"A"是不同类型的石头. 示例 1: 输入: J = "aA", S = "aAAbbbb" 输出: 3 示例 2: 输入: J = "z", S = "ZZ&…
Jewels and Stones You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character inS is a type of stone you have.  You want to know how many of the stones you have are also jewels. The…
题目标签:Hash Table 这一题很简单,题目给了两个string:J 和 S. 只要把J 里面的 char 放入HashSet,再遍历S找出有多少个石头是宝石. Java Solution: Runtime beats 97.77% 完成日期:03/06/2019 关键点:HashSet class Solution { public int numJewelsInStones(String J, String S) { int result = 0; Set<Character> je…
You're given strings J representing the types of stones that are jewels, and S representing the stones you have.  Each character in S is a type of stone you have.  You want to know how many of the stones you have are also jewels. The letters in J are…
Question 771. Jewels and Stones Solution 题目大意:两个字符串J和S,其中J中每个字符不同,求S中包含有J中字符的个数,重复的也算 思路:Set记录字符串J中的每个字符,遍历S中的字符,如果出现在Set中,count加1 Java实现: public int numJewelsInStones(String J, String S) { Set<Character> set = new HashSet<>(); int count = 0;…
LeetCode 2 Add Two Sum 解题报告 LeetCode第二题 Add Two Sum 首先我们看题目要求: You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return…
problem 771. Jewels and Stones solution1: class Solution { public: int numJewelsInStones(string J, string S) { ; unordered_set<char> js(J.begin(), J.end()); for(auto ch:S) { if(js.find(ch)!=js.end()) res++; } return res; } }; 参考 1. Leetcode_easy_771…
[LeetCode]376. Wiggle Subsequence 解题报告(Python) 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/wiggle-subsequence/description/ 题目描述: A sequence of numbers is called a wiggle sequence if the differences betw…