Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, ..., N. Your task is to find the bead whose weight is median (the ((N+1)/2)th among all beads). The foll…
Median Weight Bead Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 3162 Accepted: 1630 Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, -, N.…
链接:poj 1975 题意:n个珠子,给定它们之间的重量关系.按重量排序.求确定肯定不排在中间的珠子的个数 分析:由于n为奇数.中间为(n+1)/2,对于某个珠子.若有至少有(n+1)/2个珠子比它重或轻,则它肯定不排在中间 能够将能不能确定的权值初始化为0,能确定重量关系的权值设为1 #include<stdio.h> #include<string.h> int a[110][110]; int main() { int T,n,m,i,j,k,d,x,sum; scanf(…
Median Weight Bead Time Limit: 1000ms Memory Limit: 30000KB This problem will be judged on PKU. Original ID: 197564-bit integer IO format: %lld Java class name: Main There are N beads which of the same shape and size, but with different weight…
Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, ..., N. Your task is to find the bead whose weight is median (the ((N+1)/2)th among all beads). The foll…
描述 There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, ..., N. Your task is to find the bead whose weight is median (the ((N+1)/2)th among all beads). The following com…
Median Time Limit: 1 Second Memory Limit: 65536 KB Recall the definition of the median of elements where is odd: sort these elements and the median is the -th largest element. In this problem, the exact value of each element is not given, but relatio…
Description There are N beads which of the same shape and size, but with different weights. N is an odd number and the beads are labeled as 1, 2, ..., N. Your task is to find the bead whose weight is median (the ((N+1)/2)th among all beads). The foll…
