HDU 1711 Number Sequence (字符串匹配,KMP算法) Description Given two sequences of numbers : a1, a2, ...... , aN, and b1, b2, ...... , bM (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make aK = b1, aK+1 = b2, ...... , aK+M…

题意: 给你两个字符串,输出他们合并之后的字符串,合并的时候把A的后缀和B的前缀重叠合(或者把A的前缀和B的后缀重合).要求合并后的串既包含A右包含B, 且使得合并后的字符串尽量短,其次是使得合并后的字符串字典序尽量小. 分析: 首先A和B合并他们一定是首尾重叠相连,要求合并后字典序最小,所以当合并后串长度一样时,我们要把A或B中字典序小 的放在前面. 然后计算A的后缀和B的前缀匹配长度为len1,计算A的前缀和B的后缀匹配长度为len2. 如果len1大,那么就把A放前面.如果len2大,那么…

这是一个典型问题KMP申请书. 结果求增加两个字符串.该法的总和是相同的前缀和后缀也是字符串的字符串,您将可以合并本节. 但是,这个问题是不是问题非常明确的含义,因为不是太清楚,外观这两个字符串的顺序无关紧要,后只需要输出的最短的组合长度的结果,并后长度一样,那么就依照字典顺序,输出字典顺序在前的字符串. 思路: 1 使用kmp在s2查找s1,那么终于结束的时候next table的值就是s1前缀和s2的后缀同样的最长的长度了. 2 输入两个字符串s1和s2.那么就能够在s2中查找s1.得到长度…

Problem Description Generally speaking, there are a lot of problems about strings processing. Now you encounter another such problem. If you get two strings, such as “asdf” and “sdfg”, the result of the addition between them is “asdfg”, for “sdf” is…

题意:给你两个串,问你第二个串是从第一个串的什么位置開始全然匹配的? kmp裸题,复杂度O(n+m). 当一个字符串以0为起始下标时.next[i]能够描写叙述为"不为自身的最大首尾反复子串长度". 当发生失配的情况下,j的新值next[j]取决于模式串中T[0 ~ j-1]中前缀和后缀相等部分的长度, 而且next[j]恰好等于这个最大长度. 防止超时.注意一些细节.. 另外:尽量少用strlen.变量记录下来使用比較好,用字符数组而不用string //KMP算法模板题 //hdu…

出的超级好的一道题.至于好在哪里,请思考题目: 题意抽象出来为给定一个字符串r,找出它的一个最短后缀s,使得这个r可以被 s的某前缀+s的某前缀+......+s的某前缀+s本身构造出来. 具体题目描述如下: "Be subtle! Be subtle! And use your spies for every kind of business. " - Sun Tzu "A spy with insufficient ability really sucks" -…

题目链接: https://cn.vjudge.net/problem/HDU-3613 After an uphill battle, General Li won a great victory. Now the head of state decide to reward him with honor and treasures for his great exploit. One of these treasures is a necklace made up of 26 differe…

题目链接 Problem Description Given two sequences of numbers : a[1], a[2], ...... , a[N], and b[1], b[2], ...... , b[M] (1 <= M <= 10000, 1 <= N <= 1000000). Your task is to find a number K which make a[K] = b[1], a[K + 1] = b[2], ...... , a[K + M…

Period Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2398    Accepted Submission(s): 1187 Problem Description For each prefix of a given string S with N characters (each character has an ASCII…

Count the string Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 3797    Accepted Submission(s): 1776 Problem Description It is well known that AekdyCoin is good at string problems as well as nu…