POJ1365 - Prime Land(质因数分解)】的更多相关文章

题目大意 给定一个数的质因子表达式,要求你计算机它的值,并减一,再对这个值进行质因数分解,输出表达式 题解 预处理一下,线性筛法筛下素数,然后求出值来之后再用筛选出的素数去分解....其实主要就是字符串处理... 代码: #include <stdio.h> #include <string.h> #include <math.h> #define MAXN 10000 ]; ],cnt=; ]; void get_prime() { ; memset(check,fa…
Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing sequence of all prime numbers. We know that x > 1 can be represented in only…
Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing sequence of all prime numbers. We know that x > 1 can be represe…
题目链接: http://poj.org/problem?id=1365 题目大意: 告诉你一个数的质因数x的全部底数pi和幂ei.输出x-1的质因数的全部底数和幂 解题思路: 这道题不难.可是题意特别不好理解.对于我这样的英文渣的人.愣是一个小时没看明确 关于题意举例说明吧 比如 509 1 59 1 x = 509^1 * 59^1 = 30031 x-1 = 30030 则答案 13 1 11 1 7 1 5 1 3 1 2 1 就是 x-1 = 13^1 * 11^1 * 7^1 * 5…
Prime Land Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 3590   Accepted: 1623 Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,…
2012_p1 质因数分解 (prime.cpp/c/pas) 时间限制: 1 Sec  内存限制: 128 MB提交: 80  解决: 27[提交][状态][讨论版][命题人:外部导入] 题目描述 1.质因数分解 (prime.cpp/c/pas) [问题描述] 已知正整数 n 是两个不同的质数的乘积,试求出较大的那个质数. [输入] 输入文件名为 prime.in. 输入只有一行,包含一个正整数 n. [输出] 输出文件名为 prime.out. 输出只有一行,包含一个正整数 p,即较大的那…
1059 Prime Factors (25 分)   Given any positive integer N, you are supposed to find all of its prime factors, and write them in the format N = p​1​​​k​1​​​​×p​2​​​k​2​​​​×⋯×p​m​​​k​m​​​​. Input Specification: Each input file contains one test case whi…
http://lightoj.com/login_main.php?url=volume_showproblem.php?problem=1356 题意: 给出n个数,问最多能选几个数,使得该集合中的任意两个数中其中一个数不是另一个质数倍. 思路: 二分图的最大独立集. 那么怎么建图呢?我们按照质因数的奇偶性来分成两部分建图,如果两个数是质数倍的关系,那么就连边,最后最大独立集=点数-最大匹配. 对每个数进行质因数分解,存储每个质因数和质因数的总数,比如说P,质因数为x1,x2,x3...接下来…
题目链接: 传送门 Prime Land Time Limit: 1000MS     Memory Limit: 10000K Description Everybody in the Prime Land is using a prime base number system. In this system, each positive integer x is represented as follows: Let {pi}i=0,1,2,... denote the increasing…
4514: [Sdoi2016]数字配对 Time Limit: 10 Sec  Memory Limit: 128 MBSubmit: 726  Solved: 309[Submit][Status][Discuss] Description 有 n 种数字,第 i 种数字是 ai.有 bi 个,权值是 ci. 若两个数字 ai.aj 满足,ai 是 aj 的倍数,且 ai/aj 是一个质数, 那么这两个数字可以配对,并获得 ci×cj 的价值. 一个数字只能参与一次配对,可以不参与配对. 在…