【26】Remove Duplicates from Sorted Array】的更多相关文章

[26]Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant mem…
Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3].     用两个指针,…
LeetCode第26题 Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1)…
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […
题目描述: Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array…
题目: Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements of nums being 1, 1, 2, 2 and 3. It does…
Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array A = [1,1,1,2,2,3], Your function should return length = 5, and A is now [1,1,2,2,3]. 解题思路1: 遍历A,i表示当前遍历到的数组下标,length表示当前已重新填充的数组下标:设置一…
Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array A = […
这道题是LeetCode里的第26道题. 题目描述: 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 你不需要考虑数组中超出新长度后面的元素. 示例 2: 给定 nums = [0,0,,1,1,2,2,3,3,4], 函数应该返…
题目要求:删除排好序的含有重复元素的数组.返回去除重复后的数组长度,并更新原始数组.不能使用额外空间. 思路:要不额外的使用内存空间,那么只有遍历数组,count保持下一个不重复的数字,遍历过程中如果与该不重复数子不同或与上一个数字不同,则该数保存到count位置,并count++.如果相同,则继续遍历. public int removeDuplicates(int[] nums) { if(nums==null||nums.length==0){ return 0; } int count=…