题目链接:http://poj.org/problem?id=2187 旋转卡壳算法:http://www.cppblog.com/staryjy/archive/2009/11/19/101412.html 或 http://cgm.cs.mcgill.ca/~orm/rotcal.frame.html #include<cstdio> #include<cstring> #include<cmath> #include<iostream> #includ…

题目大意: 求最远点对距离 求凸包上的最远点对 挑战263页 #include <cstdio> #include <string.h> #include <algorithm> #include <vector> #include <cmath> using namespace std; ; ; int n; double add(double a,double b) { ; return a+b; } struct P { double x,…

题目: Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill…

旋转卡壳求凸包的直径的平方 板子题 #include<cstdio> #include<vector> #include<cmath> #include<algorithm> using namespace std; struct Point { int x, y; Point(int x=0, int y=0):x(x),y(y) { } }; typedef Point Vector; Vector operator - (const Point&…

题目:http://poj.org/problem?id=2187 学习材料:https://blog.csdn.net/wang_heng199/article/details/74477738 https://www.jianshu.com/p/74c25c0772d6 可以再倒着枚举一遍那样求凸包. 用叉积算面积来旋转卡壳. 注意在面积等于的时候就不要往后走了,不然只有两个点的数据就会死循环. #include<cstdio> #include<cstring> #inclu…

Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 32708   Accepted: 10156 Description Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a…

题目:http://poj.org/problem?id=2187 学习资料:https://blog.csdn.net/wang_heng199/article/details/74477738 https://www.jianshu.com/p/74c25c0772d6 注意求凸包时先下后上,保持逆时针: 别忘了给点排序囧. 代码如下: #include<cstdio> #include<cstring> #include<algorithm> #include&l…

题面 Bessie, Farmer John's prize cow, has just won first place in a bovine beauty contest, earning the title 'Miss Cow World'. As a result, Bessie will make a tour of N (2 <= N <= 50,000) farms around the world in order to spread goodwill between farm…

#include<iostream> #include<cstdio> #include<cmath> #include<vector> #include<algorithm> using namespace std; struct Point { int x, y; Point(int x=0, int y=0):x(x),y(y) { } }; typedef Point Vector; Vector operator - (const Po…

POJ2187 旋转卡壳算法如图 证明:对于直径AB 必然有某一时刻 A和B同时被卡住 所以旋转卡壳卡住的点集中必然存在直径 而卡壳过程显然是O(n)的 故可在O(n)时间内求出直径 凸包具有良好的性质 其中的点是有序的 对于某个点 从它之后的点与它的距离必然是一个单峰凸函数 根据这个性质也可以设计一个O(nlogn)的算法 给出代码 #include<iostream> #include<stdio.h> #include<stdlib.h> #include<…