Problem Description We define the distance of two strings A and B with same length n isdisA,B=∑(i=0 n−1) |A[i]−B[n−1−i]|The difference between the two characters is defined as the difference in ASCII.You should find the maximum length of two non-ov…
Kirinriki Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 2169 Accepted Submission(s): 879 Problem Description We define the distance of two strings A and B with same length n isdisA,B=∑i=0n−…
题目链接 Problem Description We define the distance of two strings A and B with same length n is disA,B=∑i=0n−1|Ai−Bn−1−i| The difference between the two characters is defined as the difference in ASCII. You should find the maximum length of two non-over…
We define the distance of two strings A and B with same length n is dis A,B =∑ i=0 n−1 |A i −B n−1−i | disA,B=∑i=0n−1|Ai−Bn−1−i| The difference between the two characters is defined as the difference in ASCII. You should find the maximum length of tw…
Problem Description We define the distance of two strings A and B with same length n isdisA,B=∑i=0n−1|Ai−Bn−1−i|The difference between the two characters is defined as the difference in ASCII.You should find the maximum length of two non-overlapping…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5358 题意:如题. 解法:观察式子发现,由于log函数的存在,使得这个函数的值域<=34,然后我们枚举这个值域,对于这个值域,我们用双指针O(n)维护值前缀和在这个值域里面的区间,计算即可. #include <bits/stdc++.h> using namespace std; const int maxn = 100005; typedef long long LL; LL l[35]…
