将e按从大到小排序,统计前i-1个中比 #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; struct Item { int s; int e; int x; }; int n; Item item[500010]; int a[500010],b[500010]; int lowbit(int x) { return…
Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in his field is particularly good. Farmer John has N cows (we number the cows from 1 to N). E…
Cows Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 14906 Accepted: 4941 Description Farmer John's cows have discovered that the clover growing along the ridge of the hill (which we can think of as a one-dimensional number line) in hi…
题中给出了第 i 头牛前面有多少比它矮,如果正着分析比较难找到规律.因此,采用倒着分析的方法(最后一头牛的rank可以直接得出),对于第 i 头牛来说,它的rank值为没有被占用的rank集合中的第A[i]+1大数.所以,采用树状数组维护0-1序列(表示是否被占用)的前缀和,每次再用二分得出第K大数的下标即可. 代码如下: #include <cstdio> #include <algorithm> #include <iostream> using namespace…
Cows Time Limit: 3000MS Memory Limit: 65536K Total Submissions: 17626 Accepted: 5940 Description Farmer John's cows have discovered that the clover growing along the ridge of the h…