leetcode-26-exercise_linked-list

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LeetCode 26 Remove Duplicates from Sorted Array [Array/std::distance/std::unique] <c++>

LeetCode 26 Remove Duplicates from Sorted Array [Array/std::distance/std::unique] <c++> 给出排序好的一维数组,删除其中重复元素,返回删除后数组长度,要求不另开内存空间. C++ 很简单的题目,但是第一发RE了,找了很久问题出在哪.最后单步调试发现vector.size()返回值是unsigned型的.unsigned型和int型数据运算结果还是unsigned型的.这就导致当数组为空时,nums.size(…

前端与算法 leetcode 26. 删除排序数组中的重复项

目录 # 前端与算法 leetcode 26. 删除排序数组中的重复项题目描述概要提示解析算法 # 前端与算法 leetcode 26. 删除排序数组中的重复项题目描述 26. 删除排序数组中的重复项概要一提到原地删除数组,就能立即想到双指针法,这道题本身也没什么难度,日常水题, 提示双指针解析没有思路的时候,耐心一点即可算法 /** * @param {number[]} nums * @return {number} */ const removeDuplica…

[LeetCode] 26. Remove Duplicates from Sorted Array 有序数组中去除重复项

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

Java实现 LeetCode 26 删除排序数组中的重复项

26. 删除排序数组中的重复项给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 1, 2. 你不需要考虑数组中超出新长度后面的元素. 示例 2: 给定 nums = [0,0,1,1,1,2,2,3,3,4], 函数应该返回新的长…

leetcode 26

26. Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant mem…

LeetCode 26. Remove Duplicates from Sorted Array （从有序序列里移除重复项）

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array nums …

[LeetCode] 26. Remove Duplicates from Sorted Array ☆(从有序数组中删除重复项)

[LeetCode] Remove Duplicates from Sorted Array 有序数组中去除重复项描述 Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…

LeetCode 26 Remove Duplicates from Sorted Array （移除有序数组中重复数字）

题目链接: https://leetcode.com/problems/remove-duplicates-from-sorted-array/?tab=Description 从有序数组中移除重复数字,并且返回不重复数字的个数遍历操作: 可以使用新的for循环 for (int n : nums){} 每次进行对比,并且更新第一个遇到不相等的元素的下标为i 对数组进行重新赋值操作当数组长度大于1时,ans初值为1,当数组长度为0时,返回0 参考代码 : packag…

LeetCode(26)题解:Remove Duplicates from Sorted Array

https://leetcode.com/problems/remove-duplicates-from-sorted-array/ Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this…

[LeetCode]26. 删除排序数组中的重复项(数组，双指针)

题目给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 1, 2. 你不需要考虑数组中超出新长度后面的元素. 来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/remo…

LeetCode 26 Remove Duplicates from Sorted Array

Problem: Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input ar…

Leetcode 26 Remove Duplicates from Sorted Array STL

题目本身是去重由于我很懒,所以用了STL库里的unique函数来去重,小伙伴们可以考虑自己实现去重的函数,其实并不复杂. class Solution { public: int removeDuplicates(vector<int>& nums) { return unique(nums.begin(),nums.end()) - nums.begin(); } };…

Java [leetcode 26]Remove Duplicates from Sorted Array

题目描述: Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example, Given input arra…

leetCode 26.Remove Duplicates from Sorted Array(删除数组反复点) 解题思路和方法

Remove Duplicates from Sorted Array Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory.…

leetcode 26 80 删除已排序数组中重复的数据

80. Remove Duplicates from Sorted Array II Follow up for "Remove Duplicates":What if duplicates are allowed at most twice? For example,Given sorted array nums = [1,1,1,2,2,3], Your function should return length = 5, with the first five elements…

[LeetCode] 26. 删除排序数组中的重复项

题目链接:https://leetcode-cn.com/problems/remove-duplicates-from-sorted-array/ 题目描述: 给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例: 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 1, 2.…

Leetcode 26. Remove Duplicates from Sorted Array (easy)

Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory. Exam…

[leetcode]26. Remove Duplicates from Sorted Array有序数组去重(单个元素只出现一次)

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

Leetcode 26.删除排序数组中的重复项 By Python

给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. 示例 1: 给定数组 nums = [1,1,2], 函数应该返回新的长度 2, 并且原数组 nums 的前两个元素被修改为 1, 2. 你不需要考虑数组中超出新长度后面的元素. 示例 2: 给定 nums = [0,0,1,1,1,2,2,3,3,4], 函数应该返回新的长度 5, 并且原数组 nums…

leetcode 26—Remove Duplicates from Sorted Array

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

[LeetCode] 26. Remove Duplicates from Sorted Array ☆

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. For example,Given input array nums …

[LeetCode]26. Remove Duplicates from Sorted Array删除排序数组中的重复项

Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) extra memory.…

leetcode 26 水

class Solution { public: int removeDuplicates(vector<int>& nums) { sort(nums.begin(),nums.end()); ,j=; ); nums[j++]=nums[]; ;i<nums.size();i++) { ]) continue; else nums[j++]=nums[i]; } return j ; } };…

leetCode(26):Unique Binary Search Trees

Given n, how many structurally unique BST's (binary search trees) that store values 1...n? For example, Given n = 3, there are a total of 5 unique BST's. 1 3 3 2 1 \ / / / \ \ 3 2 1 1 3 2 / / \ \ 2 1 2 3 1)结构的总数和存储的n个有序数没有关系.即存放的是1,2,3或5.6.9结果都是一样的:…

LeetCode 26：删除排序数组中的重复项 Remove Duplicates from Sorted Array

给定一个排序数组,你需要在原地删除重复出现的元素,使得每个元素只出现一次,返回移除后数组的新长度. 不要使用额外的数组空间,你必须在原地修改输入数组并在使用 O(1) 额外空间的条件下完成. Given a sorted array nums, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space f…

【LeetCode 26】删除排序数组中的重复项

题目链接 [题解] 沙比提 [代码] class Solution { public: int removeDuplicates(vector<int>& nums) { if (nums.empty()) return 0; int idx = 0; int len = nums.size(); for (int i = 1;i < len;i++) if (nums[i]!=nums[i-1]){ nums[++idx] = nums[i]; } return idx+1;…

LeetCode#26 | Remove Duplicates from Sorted Array 删除有序数组中的重复元素

一.题目 Description Given a sorted array, remove the duplicates in-place such that each element appear only once and return the new length. Do not allocate extra space for another array, you must do this by modifying the input array in-place with O(1) e…