P2990 [USACO10OPEN]牛跳房子Cow Hopscotch 题目描述 The cows have reverted to their childhood and are playing a game similar to human hopscotch. Their hopscotch game features a line of N (3 <= N <= 250,000) squares conveniently labeled 1..N that are chalked o…

单调队列优化dp; 对于每个点开个单调队列,按转移到它的点到它的距离从大到小,得分也从大到小排列. 每次枚举当前点前面的所有点,对于每个点的队列中二分一个距离小于等于它到当前点的答案值,放到当前点的队列中. //Twenty #include<algorithm> #include<iostream> #include<cstring> #include<cstdlib> #include<cstdio> #include<vector&g…

HAOI2006 (洛谷P2341)受欢迎的牛 题解 题目描述 友情链接原题 每头奶牛都梦想成为牛棚里的明星.被所有奶牛喜欢的奶牛就是一头明星奶牛.所有奶 牛都是自恋狂,每头奶牛总是喜欢自己的.奶牛之间的"喜欢"是可以传递的--如果A喜 欢B,B喜欢C,那么A也喜欢C.牛栏里共有N 头奶牛,给定一些奶牛之间的爱慕关系,请你 算出有多少头奶牛可以当明星. 输入输出格式 输入格式: 第一行:两个用空格分开的整数:N和M 第二行到第M + 1行:每行两个用空格分开的整数:A和B,表示A喜欢B…

本题是练习前缀和的好题!我们可以枚举前端点,确定一个长度为k的区间,然后利用前缀和统计区间内损坏的灯的数量,最后取最小值即可.AC代码: #include <bits/stdc++.h> using namespace std; inline int read()//快速读入 { ,x=; char c=getchar(); ') { ; c=getchar(); } ') { x=x*+c-'; c=getchar(); } return f*x; } ],s[],sum=; int mai…

P3088 [USACO13NOV]挤奶牛Crowded Cows 题目描述 Farmer John's N cows (1 <= N <= 50,000) are grazing along a one-dimensional fence. Cow i is standing at location x(i) and has height h(i) (1 <= x(i),h(i) <= 1,000,000,000). A cow feels "crowded"…

传送门啦 这是一个tarjan强连通分量与出度结合的例题. 先明确一下题意,如果这个点(缩点之后的)没有出度,这个点才能成为明星牛(明星牛的定义是:所有牛都喜欢他才可以). 由于我们进行了缩点,所以我就另外开一个数组num[i]:表示这个强连通分量中有多少个点. int sum = 0; for(int i=1;i<=cnt;i++) if(!chu[i]) ans = num[i] , sum++; if(sum >= 2) printf("0"); else print…

P3092 [USACO13NOV]没有找零No Change 题目描述 Farmer John is at the market to purchase supplies for his farm. He has in his pocket K coins (1 <= K <= 16), each with value in the range 1..100,000,000. FJ would like to make a sequence of N purchases (1 <= N…

P3047 [USACO12FEB]附近的牛Nearby Cows 题目描述 Farmer John has noticed that his cows often move between nearby fields. Taking this into account, he wants to plant enough grass in each of his fields not only for the cows situated initially in that field, but…

题意 题目链接 Sol 显然如果题目什么都不说的话需要\(\frac{n * (n - 1)}{2}\)个相对关系 然后求一下传递闭包减掉就行了 #include<bits/stdc++.h> using namespace std; const int MAXN = 1001; inline int read() { char c = getchar(); int x = 0, f = 1; while(c < '0' || c > '9') {if(c == '-') f =…

题目描述 Farmer John is at the market to purchase supplies for his farm. He has in his pocket K coins (1 <= K <= 16), each with value in the range 1..100,000,000. FJ would like to make a sequence of N purchases (1 <= N <= 100,000), where the ith p…