2018-07-31 17:47:13 问题描述: 问题求解: 本题要求在不构建二叉树的情况下对先序遍历生成的序列化字符串进行合法性验证,这里有个技巧性较强的验证方法,就是采用当前可用的指针数目进行验证,最初的时候只有一个指针,每当遇到一个节点,那么需要消耗一个指针,同时,如果是非空节点需要额外增加两个指针.在遍历过程中一旦出现了指针数目为负数的情况,那么就可以直接判false,最后如果指针数目不为0的话,也直接判false.(这里默认如果序列化为空字符串,则直接判false) public b…
331. 验证二叉树的前序序列化 331. Verify Preorder Serialization of a Binary Tree 题目描述 每日一算法2019/5/30Day 27LeetCode331. Verify Preorder Serialization of a Binary Tree…
[LeetCode]331. Verify Preorder Serialization of a Binary Tree 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/verify-preorder-serialization-of-a-binary-tree/description/ 题目描述: One way to serialize a binary tree is to use pre-order traver…
传送门 331. Verify Preorder Serialization of a Binary Tree My Submissions QuestionEditorial Solution Total Accepted: 10790 Total Submissions: 34071 Difficulty: Medium One way to serialize a binary tree is to use pre-order traversal. When we encounter a…
One way to serialize a binary tree is to use pre-oder traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
1. Description One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \…
原题链接在这里:https://leetcode.com/problems/verify-preorder-serialization-of-a-binary-tree/ 题目: One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ / \ / \ # / \ / \ / \ # # # # # # For example,…
题目如下: One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # #…
序列化二叉树的一种方法是使用前序遍历.当我们遇到一个非空节点时,我们可以记录这个节点的值.如果它是一个空节点,我们可以使用一个标记值,例如 #.     _9_    /   \   3     2  / \   / \ 4   1  #  6/ \ / \   / \# # # #   # #例如,上面的二叉树可以被序列化为字符串"9,3,4,#,#,1,#,#,2,#,6,#,#",其中#代表一个空节点.给定一串以逗号分隔的值,验证它是否是正确的二叉树的前序序列化.想出一种在不重构…
One way to serialize a binary tree is to use pre-order traversal. When we encounter a non-null node, we record the node's value. If it is a null node, we record using a sentinel value such as #. _9_ / \ 3 2 / \ / \ 4 1 # 6 / \ / \ / \ # # # # # # For…
144. Binary Tree Preorder Traversal 前序的非递归遍历:用堆来实现 如果把这个代码改成先向堆存储左节点再存储右节点,就变成了每一行从右向左打印 如果用队列替代堆,并且先存储左节点,再存储右节点,就变成了逐行打印 class Solution { public: vector<int> preorderTraversal(TreeNode* root) { vector<int> result; if(root == NULL) return res…
本质上是二叉树的root->right->left遍历. ++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 给定一个二叉树,就地的把他转换成一个链表. 例如: 给定 1 / \ 2 5 / \ \ 3 4 6 转换后的树应该向这样子: 1 \ 2 \ 3 \ 4 \ 5 \ 6 提示: 如果你观察的足够仔细,你会发现,每个还在的右孩子指针指向了,这个节点在前序遍历中的后面的那个节…
地址 https://leetcode-cn.com/contest/weekly-contest-163/problems/find-elements-in-a-contaminated-binary-tree/ 题目描述给出一个满足下述规则的二叉树: root.val == 0如果 treeNode.val == x 且 treeNode.left != null,那么 treeNode.left.val == 2 * x + 1如果 treeNode.val == x 且 treeNode…
Given a binary tree, return the preorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. Note: Recursive solution is trivial, could you do it iteratively? 一般我们提到树的遍历,最常见的有先序遍历,中序遍历,后序遍历和层序遍历,它们用递归实现起…
给定一个二叉树,以集合方式返回其中序/先序方式遍历的所有元素. 有两种方法,一种是经典的中序/先序方式的经典递归方式,另一种可以结合栈来实现非递归 Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,3,2]. OJ's Binary Tree Serialization: The s…
144. 二叉树的前序遍历 144. Binary Tree Preorder Traversal 题目描述 给定一个二叉树,返回它的 前序 遍历. LeetCode144. Binary Tree Preorder Traversal 示例: 输入: [1,null,2,3] 1 \ 2 / 3 输出: [1,2,3] 进阶: 递归算法很简单,你可以通过迭代算法完成吗? Java 实现 Iterative Solution import java.util.LinkedList; import…
++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ 给定一个二叉树,返回他的中序遍历的节点的values. 例如: 给定一个二叉树 {1,#,2,3}, 1 \ 2 / 3 返回 [1,3,2]. 笔记: 递归解决方案是微不足道的,你可以用迭代的方法吗? 困惑什么"{1,#,2,3}" 的意思吗? > read more on how binary tree is s…
Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tree where the original right nodes turned into left leaf nodes. Return…
Given a binary tree, return the level order traversal of its nodes' values. (ie, from left to right, level by level). For example:Given binary tree{3,9,20,#,#,15,7}, 3 / \ 9 20 / \ 15 7 return its level order traversal as: [ [3], [9,20], [15,7] ] con…
Given a binary tree, return the inorder traversal of its nodes' values. For example:Given binary tree{1,#,2,3}, 1 \ 2 / 3 return[1,3,2]. Note: Recursive solution is trivial, could you do it iteratively? confused what"{1,#,2,3}"means? > read m…
Given a binary tree where all the right nodes are either leaf nodes with a sibling (a left node that shares the same parent node) or empty, flip it upside down and turn it into a tree where the original right nodes turned into left leaf nodes. Return…
Binary Tree Preorder Traversal Given a binary tree, return the preorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [1,2,3]. Note: Recursive solution is trivial, could you do it iteratively? Solution: 递归…
详见:剑指 Offer 题目汇总索引:第6题 Binary Tree Postorder Traversal            Given a binary tree, return the postorder traversal of its nodes' values. For example: Given binary tree {1,#,2,3}, 1 \ 2 / 3 return [3,2,1]. Note: Recursive solution is trivial, could…
找到所有根到叶子的路径 深度优先搜索(DFS), 即二叉树的先序遍历. /** * Definition for a binary tree node. * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */ class Solution { public: vector<string> v…