题意:细菌爱好者在盒子里面培养细菌.最初盒子是空的,每天可以往盒子里面添加任意数目的细菌,而且每天每个细菌会分裂成两个.在某一时刻要想获得某一数量的细菌,要求最初放置的最少的细菌数目. 思路: 求出 n 的二进制形式中 1 的个数即可. 代码: #include<iostream> #include<cstdio> #include<cstdlib> #include<cstring> #include<queue> #include<al…

You are a lover of bacteria. You want to raise some bacteria in a box. Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night, every bacterium in the box will split into two bacteria. You hope to se…

A. Raising Bacteria time limit per test 1 second memory limit per test 256 megabytes input standard input output standard output You are a lover of bacteria. You want to raise some bacteria in a box. Initially, the box is empty. Each morning, you can…

在培养皿中,每个细胞每天会繁殖,数量*2 我们可以在任意天加入任意数量的细胞入培养皿中. 想要知道最少加入多少个细胞,可以使得有一天,培养皿中细胞的数量会恰好为x 其实就是输出X的二进制中有多少个1 Sample test(s)input5output2input8output1 # include <iostream> # include <cstdio> # include <cstring> # include <algorithm> # includ…

Codeforces Round#320 Div2 先做个标题党,骗骗访问量,结束后再来写咯. codeforces 579A Raising Bacteria codeforces 579B Finding Team Member codeforces 579C A Problem about Polyline codeforces 579D "Or" Game codeforces 579E Weakness and Poorness codeforces 579F LCS Aga…

题目传送门:Raising Bacteria //问题描述:一个盒子里面放一个细菌在一天可以增生两个细菌. 现在已知盒子里面细菌的个数,问你最初放多少个细菌可以增生盒子里面的细菌数量 //输入:盒子中细菌的数量 //输出:最初至少放的细菌数量 //算法分析:从2开始累乘过程计数! #include <iostream> #include <cstring> #include <algorithm> using namespace std; typedef long lo…

Raising Bacteria 题意:盒子里面的细菌每天会数量翻倍,你可以在任意一天放任意多的细菌,最后要使得某天盒子里面的细菌数量等于x,求至少要放多少个细菌 思路:显然,翻倍即为二进制左移一位,那么放入一个细菌,到第二天就变成2个二进制下即为1->10对于任意二进制数 如:1001110,只需要在第一天放1个,第4.5.6天各放一个,再等一天,就可以了.所以答案显然是x在二进制下1的个数. Finding Team Member 题意:2n个人,每两个人组合的队伍有aij的力量.每个人都希…

1.前言 虽然这次我依旧没有参加正式比赛,但是事后还是看了看题目的...一般不怎么刷Codeforces. A.Raising Bacteria You are a lover of bacteria. You want to raise some bacteria in a box. Initially, the box is empty. Each morning, you can put any number of bacteria into the box. And each night…

A. Raising Bacteria 计算一下x的bitcount就是答案. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> using namespace std; int bitcount(int x) { ; while(x) { ) ans++; x >>= ; } return ans; } int main() { int x…

D. Dima and Bacteria time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Dima took up the biology of bacteria, as a result of his experiments, he invented k types of bacteria. Overall, there a…