C. Coloring Trees   ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where n trees grow. They decided to be naughty and color the trees in the park. The trees are numbered with integers from 1 to n from left to right…
Coloring Trees Problem Description: ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where n trees grow. They decided to be naughty and color the trees in the park. The trees are numbered with integers from 1 to n fr…
C. Coloring Trees 题目连接: http://www.codeforces.com/contest/711/problem/C Description ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where n trees grow. They decided to be naughty and color the trees in the park. The…
C. Coloring Trees time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where n trees grow. They decided to be…
题目链接 http://codeforces.com/contest/711/problem/C Description ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where n trees grow. They decided to be naughty and color the trees in the park. The trees are numbered wit…
题目:https://codeforces.com/problemset/problem/711/C 题意:给你n,m,k,代表n个数的序列,有m种颜色可以涂,0代表未涂颜色,其他代表已经涂好了,连着一段是相同颜色的是一个连通块,求正好有k个连通块的最小花费 思路:首先每个位置有可能有m中颜色,而且要满足k个,我们我们可以推出所有情况 dp[n][m][k] n代表前n个数 m代表当前涂m色 k代表满足k个了 #include<cstdio> #include<cmath> #in…
题目大意:有n个点,由m种颜料,有些点没有涂色,有些点已经涂色了,告诉你每个点涂m种颜色的价格分别是多少, 让你求将这n个点分成k段最少需要多少钱. 思路:动态规划,我们另dp[ i ][ j ][ k ] 表示到i个点为止,分成j段,最后一段的颜色为k的最少值,然后就能很容易地 写出状态转移方程. #include<bits/stdc++.h> #define ll long long using namespace std; ; const ll inf=0x3f3f3f3f3f3f3f3…
C. Coloring Trees time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output ZS the Coder and Chris the Baboon has arrived at Udayland! They walked in the park where ntrees grow. They decided to be n…
题目链接:http://codeforces.com/contest/283/problem/B 思路: dp[now][flag]表示现在在位置now,flag表示是接下来要做的步骤,然后根据题意记忆化搜索记忆,vis数组标记那些已经访问过的状态. #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define REP(i, a, b) for (i…
http://codeforces.com/group/1EzrFFyOc0/contest/711/problem/C https://blog.csdn.net/qq_36368339/article/details/78568585?locationNum=6&fps=1  题解 题意:(真难理解)有n个点,m种颜色,你要给n个点上没有颜色的点染色.每个点i对应染的颜色j有一个颜料消耗,p[i][j]是点i染成j颜色的花费,你必须保证有k段颜色的点,输出最少花费多少颜料. 思路:题意稍微不…