Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…
题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路比较简单,不多说啦 几个需要注意的点: 1. 高位多个为0的,需要进行判断 2. 如果乘数为0的话,可以直接跳过,能节省不少时间 3. string 的两个使用 1) 创建有…
题目描述: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路: 设置数组记录单个位置相乘的结果,最后负责相加进位. 代码如下: public class Solution { public String multiply(St…
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT use internal library su…
# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 43: Multiply Stringshttps://leetcode.com/problems/multiply-strings/ Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbit…
Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 将乘积逐位逆序存放在int数组result中. 记num1当前为第i位,num2当前为第j位,则乘积存放在result[(n1-1-i)+(n2-1-j…
Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 各个位相乘,保存在数组中,最后再处理进位. 如 123*456 4,5,6 8,10,12 12,15,18…
题目要求:Multiply Strings Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 分析: 参考网址:http://blog.csdn.net/pickless/article/details/9235907 利用竖式的思想,…
一天一道LeetCode系列 (一)题目 Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. Converting the input string to integer is NOT allowed. You should NOT us…
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/multiply-strings/description/ 题目描述 Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and nu…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意分析: 本题是求两个用string表示的非负大数的乘积,乘数可以是任意大小. 解答: 可以用一个临时List表示乘积的每一位,然后对两个乘数每一位两两相乘,并将结果填到相应的List…
Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Note: You must not use any built-in BigInteger library or convert the inputs to integer directly. 暴力法 转换为数值型变量再进行…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 解题思路一: BigInteger!!! JAVA实现如下: import java.math.BigInteger; public class Solution { static pu…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:直观思路,就是模拟乘法过程.注意进位.我写的比较繁琐. string multiply(string num1, string num2) { vector<int> v1, v…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 第一眼看到这个题目,潜意识里觉得直接将字符串转换为数字相乘,然后将结果再转换为字符串,难道这题考的是字符串与数值之间的转换? 细看,发现数字可能非常大,那么问题来了:这个数据类型怎么定义…
题目: Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 题意给两个字符串表示的数字,计算他们的乘积. 其实就是手写一个大数乘法,先翻转字符串便于从低位开始计算. 模拟乘法的运算过程,把中间结果存在data中,最后在考虑data的进位并…
DescriptionHintsSubmissionsDiscussSolution Pick One Given two non-negative integers num1 and num2 represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Out…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. string multiply(string& num, char ch){ '; string s; ; int x; ; i>=; i--){ x = (num[i]-') *…
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 思路:首先确定结果的位数,难点在于知道结果中的每一位,是乘数中的哪两位相乘贡献的:是num2中的i-len1+1到i中的数分别乘以num1中的i-j相加而得的,并且要注意不能超过num2…
Given two non-negative integers num1 and num2represented as strings, return the product of num1 and num2, also represented as a string. Example 1: Input: num1 = "2", num2 = "3" Output: "6" Example 2: Input: num1 = "123&q…
