有n个节点以1为根节点的树,给你树的边关系u-v,一开始每个节点都有一个苹果,接下来有两种操作,C x改变节点x的苹果状态,Q x查询x为根的树的所有苹果个数.   求出树的dfs序,st[i]保存i的进入时间戳,ed[i]保存i的退出时间戳,则st[i]到ed[i]就是子树节点的对应时间戳. 每个节点打了两次时间戳,其中ed[i]会等于最后访问的一个子节点的st[i]. 于是用线段树/树状数组的单点修改和区间求和就可以解决. #include<cstdio> #define N 100005…

[POJ 2486] Apple Tree(树型dp) Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 8981   Accepted: 2990 Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each…

Apple Tree Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each node has an amount of apples. Wshxzt starts her happy trip at one node. She can eat up all the apple…

http://poj.org/problem?id=3321 http://acm.hdu.edu.cn/showproblem.php?pid=3887 POJ 3321: 题意:给出一棵根节点为1的边不一定的树,然后给出问题:询问区间和 或者 节点值更新. HDU 3887: 题意:和POJ 3321的题意差不多,只不过对每个节点询问不包含该节点的区间和 思路:今天才学了下才知道有DFS序这种东西,加上树状数组处理一下区间和 和 节点更新. DFS序大概就是我们在DFS遍历一棵树的时候,在进…

[poj2486]Apple Tree Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 10800   Accepted: 3629 Description Wshxzt is a lovely girl. She likes apple very much. One day HX takes her to an apple tree. There are N nodes in the tree. Each node ha…

[题目链接]:http://codeforces.com/problemset/problem/348/B [题意] 给你一棵树; 叶子节点有权值; 对于非叶子节点: 它的权值是以这个节点为根的子树上的叶子节点的权值的和; 定义一棵树是平衡的,当且仅当,每个节点的所有直系儿子的权值都相等; 问你要使得这棵树平衡,最少需要删除掉多少叶子节点上的权值; [题解] 在第一个dfs里面求出d[i]和s[i]; 设d[i]表示以i为根的子树要平衡的话最少需要多少权值(注意这里不是说最少要删去多少权值,而是…

Apple Tree Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 22131   Accepted: 6715 Description There is an apple tree outside of kaka's house. Every autumn, a lot of apples will grow in the tree. Kaka likes apple very much, so he has been…

题目大意:对树进行m次操作,有两类操作,一种是改变一个点的权值(将0变为1,1变为0),另一种为查询以x为根节点的子树点权值之和,开始时所有点权值为1. 分析: 对树进行dfs,将树变为序列,记录每个点进栈出栈的时间戳作为其对应区间的左右端点,那么其子节点对应区间必在该区间内,对这段区间求和即可,用树状数组进行修改与求和. 代码: program apple; type point=^node; node=record x:longint; next:point; end; var a:..]o…

Apple Catching 直接翻译了 Descriptions 有两棵APP树,编号为1,2.每一秒,这两棵APP树中的其中一棵会掉一个APP.每一秒,你可以选择在当前APP树下接APP,或者迅速移动到另外一棵APP树下接APP(移动时间可以忽略不计),但由于却乏锻炼,你最多移动W次.问在T秒内,你最多能收集多少个APP.假设你开始站在1号APP树下. Input 第1行:两个整数T(1 < = T< = 1000)和W(1 < = W< = 30)第2..T+1行:1或2,代…

Tree Time Limit: 1000MS   Memory Limit: 30000K Total Submissions: 11570   Accepted: 3626 Description Give a tree with n vertices,each edge has a length(positive integer less than 1001).  Define dist(u,v)=The min distance between node u and v.  Give a…