// HDU5634 Rikka with Phi 线段树 // 思路:操作1的时候,判断一下当前区间是不是每个数都相等,在每个数相等的区间上操作.相当于lazy,不必更新到底. #include <bits/stdc++.h> using namespace std; #define clc(a,b) memset(a,b,sizeof(a)) #define inf 0x3f3f3f3f #define lson l,mid,rt<<1 #define rson mid+1,r…

题意:bc round 73 div1 D 中文题面 分析:注意到10^7之内的数最多phi O(log(n))次就会变成1, 因此可以考虑把一段相同的不为1的数缩成一个点,用平衡树来维护. 每次求phi的时候就在平衡树上取出这个区间然后暴力求phi,如果一段数变成了1, 就在平衡树里面删掉它,最后统计答案的时候只要把区间中被删去的1加回答案即可, 时间复杂度O((n + m)logn) 注:平衡树,写起来麻烦(然后其实我也不会写) 但是题解当中说把一段相同的数缩成一个点,就很好 所以用线段树,…

Chosen Problem Solving and Program design as an optional course, you are required to solve all kinds of problems. Here, we get a new problem. There is a very long board with length L centimeter, L is a positive integer, so we can evenly divide the bo…

2016暑假多校联合---Rikka with Sequence (线段树) Problem Description As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: Yuta has an array A with n numbers. Then he make…

Rikka with Sequence 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5828 Description As we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: Yuta has an array A wi…

题目链接 http://acm.hdu.edu.cn/showproblem.php?pid=6089 题解 这波强行维护搞得我很懵逼... 扫描线,只考虑每个点能走到左上方(不包括正上方,但包括正左方)的哪些点,然后旋转四次坐标系处理 所有询问和操作点按照先\(x\)后\(y\)坐标的顺序排序,然后枚举每一行,按\(y\)从小到大的顺序枚举这一行每个点 对于一个询问点找出前面最后一个操作点,那么要求的就是一个矩形减去一个区间内所有后缀最大值的和 然后这个东西可以用线段树直接维护,记录个区间最大…

由于上下线段是不可能有交点的 可以先看左右线段树,按照y递增的顺序,对点进行排序. 升序构造,那么对于从某一点往下的射线,对于L,R进行区间覆盖,线段交点个数就是单点的被覆盖的次数. 降序构造,那么对于从某个点从下往上的射线,所有y坐标比期大的点都进行了区间覆盖,那么单点就是答案. 最近脑子不太好...思路一定要清晰啊... #include<iostream> #include<string.h> #include<algorithm> #include<std…

分析:这个题和bc round 73应该是差不多的题,当时是zimpha巨出的,那个是取phi,这个是开根 吐槽:赛场上写的时候直接维护数值相同的区间,然后1A,结果赛后糖教一组数据给hack了,仰慕 由于是开根,所以存在两个数刚开始差为1,加上某数再开根依旧是差1,这样维护相同数区间的就没用了 比如(2,3) +6-->(8,9)开根-->(2,3)如果全是这样的操作,即使维护相同的数,每次开根的复杂度都是O(N),不T才怪 这样只需要维护区间最大值最小值,当差1的时候,看看是否开根后还是差…

Problem DescriptionAs we know, Rikka is poor at math. Yuta is worrying about this situation, so he gives Rikka some math tasks to practice. There is one of them: Yuta has an array A with n numbers. Then he makes m operations on it. There are three ty…

链接:https://www.nowcoder.com/acm/contest/148/A来源:牛客网 题目描述 Today, Rikka is going to learn how to use BIT to solve some simple data structure tasks. While studying, She finds there is a magic expression in the template of BIT. After searching for some l…