Given an input string, reverse the string word by word. Example: Input: "the sky is blue",Output: "blue is sky the".Note: A word is defined as a sequence of non-space characters.Input string may contain leading or trailing spaces. Howe…
Given a string, you need to reverse the order of characters in each word within a sentence while still preserving whitespace and initial word order. Example 1: Input: "Let's take LeetCode contest" Output: "s'teL ekat edoCteeL tsetnoc"…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. Clarification: What constitutes a…
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 日期 题目地址:https://leetcode.com/problems/reverse-words-in-a-string/description/ 题目描述 Given an input string, reverse the string word by word. Example 1: Input: "the sky is blue"…
给定一个字符串,翻转字符串中的每个单词.例如,给定 s = "the sky is blue",返回 "blue is sky the".对于C程序员:请尝试用O(1) 时间复杂度的原地解法.说明:    什么构成一个词?    一系列非空格字符组成一个词.    输入字符串是否可以包含前导或尾随空格?    是.但是,您的反转字符串不应包含前导或尾随空格.    两个单词之间多空格怎么样?    将它们缩小到反转字符串中的单个空格.详见:https://leetc…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". Update (2015-02-12): For C programmers: Try to solve it in-place in O(1) space. 这题遇到的困难主要是细节地方处理的不好:(1)空格的处理,(2…
Given an input string, reverse the string word by word. For example, Given s = "the sky is blue", return "blue is sky the". 解题思路: 本题方法多多,最简单的方式直接按“ ” spilt即可,JAVA实现如下: public String reverseWords(String s) { if (s == null || s.length()…
Given an input string, reverse the string word by word. For example,Given s = "the sky is blue",return "blue is sky the". Update (2015-02-12):For C programmers: Try to solve it in-place in O(1) space. 倒序字符串. 注意使用BufferString,因为如果使用Stri…
[抄题]: Given an input string, reverse the string word by word. Example: Input: "the sky is blue", Output: "blue is sky the". [暴力解法]: 时间分析: 空间分析: [优化后]: 时间分析: 空间分析: [奇葩输出条件]: [奇葩corner case]: [思维问题]: 打碎成数组后再添加,居然有看不懂的bug. public class So…
原题地址 将单词按空格分词,然后倒序拼接即可 代码: void reverseWords(string &s) { vector<string> words; ; ; ; i < s.length(); i++) { if (s[i] == ' ') { ) words.push_back(s.substr(start, len)); len = ; } else { ) { start = i; len = ; } else len++; } } ) words.push_ba…