一.题目 Common Subsequence 二.分析 比较基础的求最长升序子序列. $DP[i][j]$表示的是字符串$S1[1...i]$与$S2[1...j]$的最长公共子序列长度. 状态转移:$$if s1[i] == s2[j]    DP[i][j] = DP[i-1][j-1] + 1$$  $$if s1[i] != s2[j]    DP[i][j] = max(DP[i-1][j], DP[i][j-1]$$ 相等时好理解,不相等的时候就是考虑两个字符串分别加上这个字符后,…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 28494    Accepted Submission(s): 12735 Problem Description A subsequence of a given sequence is the given sequence with some e…

Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 43132   Accepted: 17472 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…

HDOJ 1159 Common Subsequence[DP] Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 44280 Accepted Submission(s): 20431 Problem Description A subsequence of a given sequence is the given sequence wit…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=1159 http://acm.hust.edu.cn/vjudge/contest/view.action?cid=28195#problem/A Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 17621…

HDOJ 1423 Greatest Common Increasing Subsequence [DP][最长公共上升子序列] Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8768 Accepted Submission(s): 2831 Problem Description This is a problem from ZOJ 24…

POJ_2533 Longest Ordered Subsequence[DP][最长递增子序列] Longest Ordered Subsequence Time Limit: 2000MS Memory Limit: 65536K Total Submissions: 58448 Accepted: 26207 Description A numeric sequence of ai is ordered if a1 < a2 < - < aN. Let the subsequenc…

POJ 1458 Common Subsequence(LCS最长公共子序列)解题报告 题目链接:http://acm.hust.edu.cn/vjudge/contest/view.action?cid=87730#problem/F 题目: Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 43388   Accepted: 17613 Description A subsequen…

Common Subsequence Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 37614   Accepted: 15058 Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = < x1, x2, ..…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 39559    Accepted Submission(s): 18178 Problem Description A subsequence of a given sequence is the given sequence with some el…

解题思路:先注意到序列和串的区别,序列不需要连续,而串是需要连续的,先由样例abcfbc         abfcab画一个表格分析,用dp[i][j]储存当比较到s1[i],s2[j]时最长公共子序列的长度 a    b    f    c    a    b 0    0    0    0    0   0    0 a  0    1     1    1    1   1    1 b  0    1     2    2    2   2    2 c  0    1     2  …

Problem Description A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, -, xm> another sequence Z = <z1, z2, -, zk> is a subsequence of X if there exists a strictly…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 48378    Accepted Submission(s): 22242 Problem Description A subsequence of a given sequence is the given sequence with some e…

Problem C: Longest Common Subsequence Sequence 1: Sequence 2: Given two sequences of characters, print the length of the longest common subsequence of both sequences. For example, the longest common subsequence of the following two sequences: abcdgh…

Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 37725    Accepted Submission(s): 17301 Problem Description A subsequence of a given sequence is the given sequence with some el…

传送门: http://acm.hdu.edu.cn/showproblem.php?pid=1159 Common Subsequence Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 47676    Accepted Submission(s): 21890 Problem Description A subsequence of…

P4303 [AHOI2006]基因匹配 标签(空格分隔): 考试题 nt题 LCS优化 [题目] 卡卡昨天晚上做梦梦见他和可可来到了另外一个星球,这个星球上生物的DNA序列由无数种碱基排列而成(地球上只有4种),而更奇怪的是,组成DNA序列的每一种碱基在该序列中正好出现5次!这样如果一个DNA序列有N种不同的碱基构成,那么它的长度一定是5N. 卡卡醒来后向可可叙述了这个奇怪的梦,而可可这些日子正在研究生物信息学中的基因匹配问题,于是他决定为这个奇怪星球上的生物写一个简单的DNA匹配程序. 为了…

问题 说明该问题在生物学中的实际意义 Biological applications often need to compare the DNA of two (or more) different organisms. A strand of DNA consists of a string of molecules called bases, where the possible bases are adenine, guanine, cytosine, and thymine(腺嘌呤,鸟嘌…

Common Subsequence Time Limit: 2 Seconds      Memory Limit: 65536 KB A subsequence of a given sequence is the given sequence with some elements (possible none) left out. Given a sequence X = <x1, x2, ..., xm> another sequence Z = <z1, z2, ..., zk…

多串LCS很适合SA但是我要学SAM 对第一个串求SAM,然后把剩下的串在SAM上跑,也就是维护p和len,到一个点,如果有ch[p][c],就p=ch[p][c],len++,否则向fa找最下的有c[p][c]的p,然后len=dis[p]+1,p=ch[p][c],否则就p=root,len=0(这个len每到一个节点就更新这个节点的f) 然后注意到在parent树上,因为每个节点代表的right集合是儿子的并集,所以f[u]是可以更新f[fa[u]]的,所以从底向上更新一遍(注意先更新!!…

题目链接:https://vjudge.net/contest/124428#problem/A 题目大意:给出两个字符串,求其最长公共子序列的长度. 最长公共子序列算法详解:https://blog.csdn.net/hrn1216/article/details/51534607     (其中的图解很详细)   根据图解理解下面代码 #include<cstdio> #include <string> #include<cstring> #include<i…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 解题思路:任意先给出两个字符串 abcfbc abfcab,用dp[i][j]来记录当前最长的子序列,则如果有x[i]与y[j]相等的话,则相当于公共子序列的长度在dp[i-1][j-1]上增加1, 如果x[i]与y[j]不相等的话,那么dp[i][j]就取得dp[i][j-1]和dp[i-1][j]中的最大值即可.时间复杂度为O(mn) 反思:大概思路想出来之后,因为dp数组赋初值调了很久,…

题目链接:http://poj.org/problem?id=1458 这是一道最长公共子序列的模板题: #include<iostream> #include<string> #include<cstdio> #include<cstring> #include<queue> #include<map> #include<stack> #include<set> #include<vector>…

嘤嘤嘤,我又来了,刚A完就写,这个沙雕题有丶恶心.                  ???时间4.11发现所有表情包都莫得了 题目: In an n×n chessboard, Prince and Princess plays a game. The squares in the chessboard are numbered 1, 2, 3, . . . , n∗n, as shown below:   Prince stands in square 1, make p jumps and…

题目地址:http://ac.jobdu.com/problem.php?pid=1056 题目描述: 输入两个正整数,求其最大公约数. 输入: 测试数据有多组,每组输入两个正整数. 输出: 对于每组输入,请输出其最大公约数. 样例输入: 49 14 样例输出: 7 来源: 2011年哈尔滨工业大学计算机研究生机试真题 #include <stdio.h> int gcd1 (int a, int b){ if (b == 0) return a; else return gcd1 (b, a…

14. Longest Common Prefix Write a function to find the longest common prefix string amongst an array of strings. 寻找一个数组中最长的公共前缀 例如["baaa","caaabbb","aaaa"]输出"aaa" 结题思路: 判断非空的情况在进行计算 取第一个字符串最为标杆进行对比,因为最终结果一定在第一位中 用第一…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1159 题意: 求最长公共子序列. 题解: (LCS模板题) 表示状态: dp[i][j] = max len of LCS a串匹配到第i位,b串匹配到第j位,此时的最长公共子序列长度. 如何转移: 首先,一个明显的决策是,如果a[i] == b[j],那么此一定要匹配.(贪心) 所以分两种情况: (1)a[i] == b[j]:dp[i][j] = dp[i-1][j-1] + 1 (2)a[i]…

题目链接:https://vjudge.net/problem/POJ-2250 题目大意:给出n组case,每组case由两部分组成,分别包含若干个单词,都以“#”当结束标志,要求输出最长子序列. #include <iostream> #include <string> using namespace std; ], b[], ans[]; ][], num[][]; void LCSLength() { memset(dp, , sizeof(dp)); memset(num…

Given k strings, find the longest common prefix (LCP).   Example For strings "ABCD", "ABEF" and "ACEF", the LCP is "A" For strings "ABCDEFG", "ABCEFG" and "ABCEFA", the LCP is "ABC…

任意门:http://poj.org/problem?id=1159 解题思路: LCS + 滚动数组 AC code: #include <cstdio> #include <iostream> #include <algorithm> #define INF 0x3f3f3f3f #define LL long long using namespace std; ; char a[MAXN], b[MAXN]; ][MAXN]; int main() { int l…