If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write…

1058 A+B in Hogwarts (20 分)   If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enou…

1058 A+B in Hogwarts (20分) 题目: If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy eno…

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write…

题意: 输入两组,每组三个非负整数A,B,C(A<=1e7,B<17,C<29),输出相加的和.(类似个位上29进制,十位上17进制运算) AAAAAccepted code: #define HAVE_STRUCT_TIMESPEC #include<bits/stdc++.h> using namespace std; int main(){ ios::sync_with_stdio(false); cin.tie(NULL); cout.tie(NULL); int a…

无语,这种水题还出,浪费时间,但又不得不A... #include <iostream> #include <cstdio> #include <algorithm> #include <string.h> #include <cmath> #define SICKLE 17 #define KNUT 29 using namespace std; int a1,a2,a3; int b1,b2,b3; int main() { scanf(&q…

Shuffling is a procedure used to randomize a deck of playing cards. Because standard shuffling techniques are seen as weak, and in order to avoid "inside jobs" where employees collaborate with gamblers by performing inadequate shuffles, many cas…

To prepare for PAT, the judge sometimes has to generate random passwords for the users. The problem is that there are always some confusing passwords since it is hard to distinguish 1 (one) from l (L in lowercase), or 0 (zero) from O (o in uppercase)…

#include <stdio.h> int main() { ]; ]; ],&ans1[],&ans1[],&ans2[],&ans2[],&ans2[])!=EOF) { ans1[]+=ans2[]; ans1[]+=ans2[]; ans1[]+=ans2[]; ans1[]+=ans1[]/; ans1[]=ans1[]%; ans1[]+=ans1[]/; ans1[]=ans1[]%; printf(],ans1[],ans1[]); }…

简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #include<queue> #include<algorithm> using namespace std; int a1,b1,c1; int a2,b2,c2; int ans1,ans2,ans3; int main() { scanf("%d.%d.%d",&…