题面 传送门 前置芝士 \(bsgs\),\(Cipolla\) 题解 因为题目保证\(p\bmod 10\)是完全平方数,也就是说\(p\bmod 5\)等于\(1\)或\(-1\),即\(5\)是模\(p\)的二次剩余(法老讲过,我忘了为啥了--) 然后我们需要用\(Cipolla\)求出\(c=\sqrt{5}\),并记\(p={1+c\over 2}\) 用斐波那契数列的通项公式代入,方程可以变为 \[{1\over c}\left(p^n-(-1)^n{1\over p^n}\righ…

题意 定义 $F_n$ 为 $$F_n = \left\{\begin{matrix}0, n=0\\ 1, n=1 \\F_{n-1} + F_{n-2}, n > 1\end{matrix}\right.$$ 现给你一个素数 $p$ 和一个非负整数 $C$,你需要最小的非负整数 $n$,使得 $F_n \equiv C (mod \ p)$. 分析 因为题目保证 $p \ mod \ 10$ 是一个完全平方数,也就是说 $p \ mod \ 5$ 等于1或-1,即5是模$p$ 的二次剩余(据…

https://github.com/Premiumlab/Python-for-Algorithms--Data-Structures--and-Interviews/blob/master/Mock%20Interviews/Large%20Search%20Engine%20Company%20/Search%20Engine%20Company%20-%20Interview%20Problems%20-%20SOLUTIONS/Phone%20Screen.ipynb Phone Sc…

fibonacci number & fibonacci sequence https://www.mathsisfun.com/numbers/fibonacci-sequence.html http://www.shuxuele.com/numbers/fibonacci-sequence.html fibonacci sequence with cache "use strict"; /** * * @author xgqfrms * @license MIT * @co…

Buge's Fibonacci Number Problem Description snowingsea is having Buge’s discrete mathematics lesson, Buge is now talking about the Fibonacci Number. As a bright student, snowingsea, of course, takes it as a piece of cake. He feels boring and soon com…

Problem Introduction The Fibonacci numbers are defined as follows: \(F_0=0\), \(F_1=1\),and \(F_i=F_{i-1}+F_{i-2}\) for $ i \geq 2$. Problem Description Task.Given an integer \(n\),find the last digit of the \(n\)th Fibonacci number \(F_n\)(that is ,…

Problem Introduction The Fibonacci numbers are defined as follows: \(F_0=0\), \(F_1=1\),and \(F_i=F_{i-1}+F_{i-2}\) for $ i \geq 2$. Problem Description Task.Given an integer \(n\),find the \(n\)th Fibonacci number \(F_n\). Input Format.The input con…

根据CC150的解决方式和Introduction to Java programming总结: 使用了两种方式,递归和迭代 CC150提供的代码比较简洁,不过某些细节需要分析. 现在直接运行代码,输入n(其中用number代替,以免和方法中的n混淆)的值,可以得出斐波那契数. 代码如下: /* CC150 8.1 Write a method to generate the nth Fibonacci number Author : Mengyang Rao note : Use two me…

又对啦...开心~~~~ 只是代码可能不符合PEP标准什么的... Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... By considering the terms in the Fibo…

斐波那契数列(Fibonacci Number)从数学的角度是以递归的方法定义的: \(F_0 = 0\) \(F_1 = 1\) \(F_n = F_{n-1} + F_{n-2}\) (\(n \geq 2\)) C# 的递归算法实现如下: /// <summary> /// 返回指定序数的 Fibonacci number /// </summary> /// <param name="index"></param> /// <…