Remove Element: Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory. The order of elements can be changed. It…

Remove Element算是LeetCode的一道水题,不过这题也有多种做法,现就我所知的几种做一点讨论. 题目链接:https://leetcode.com/problems/remove-element/ 题目描述:Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. I…

原题链接在这里:https://leetcode.com/problems/remove-element/ 题目: Given an array and a value, remove all instances of that value in place and return the new length. Do not allocate extra space for another array, you must do this in place with constant memory…

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 这道题让我们移除一个数组中和给定值相同的数字,并返回新的数组的长度.是一道比较容易的题,我们只需要一个变量用来计数…

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 这题做下来感觉技巧性比较强,解出第一种解法以后我又尝试了另外两种解法,一个比一个简单...我一开始却折腾出了最晦涩…

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 中文:给定一个数组和一个数值,去除这个数值全部出现位置,并返回新数组的长度. 元素的顺序能够改变.除了新的长度,你…

Given an array and a value, remove all instances of that value in place and return the new length. The order of elements can be changed. It doesn't matter what you leave beyond the new length. 题意:删除给定的数,然后返回新的长度. 思路:这题的思路和sort colors差不多,是其简化版.大致的思路是:…

class Solution(object): def removeElement(self, nums, val): """ :type nums: List[int] :type val: int :rtype: int """ if len(nums) <= 0: return 0 k=0 for i in nums: if i != val: nums[k]=i k+=1 return k…

class Solution { public: int removeElement(int A[], int n, int elem) { ]; int i,num=n; ;i<n;i++){ //一共要对比n次,不能用n来处理,会影响循环 if(*p==elem){ if(p==e) //已经处理到最后一个相同,只需总数减1 num--; else{ *p=*e; e--; num--; } } else p++; } return num; } }; 题意:给一个整型数组(无序),删除规定…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 27: Remove Elementhttps://oj.leetcode.com/problems/remove-element/ Given an array and a value, remove all instances of that value in place and return the new length.The order of elements ca…