Teacher Bo 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 Description Teacher BoBo is a geography teacher in the school.One day in his class,he marked N points in the map,the i-th point is at (Xi,Yi).He wonders,whether there is a tetrad (A,B,C,…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 题目大意: 给n个点,坐标范围0~m(n,m<=105),求是否存在2个点对满足哈夫曼距离相等. 题目思路: [模拟] 乍一看n2绝对T了,但是细想之下发现,坐标范围只有105,那么哈夫曼距离最多就2x105种,所以当循环超出这个范围时肯定能找到解(抽屉原理). // //by coolxxx // #include<iostream> #include<algorithm&g…

Teacher Bo 题目连接: http://acm.hdu.edu.cn/showproblem.php?pid=5762 Description Teacher BoBo is a geography teacher in the school.One day in his class,he marked N points in the map,the i-th point is at (Xi,Yi).He wonders,whether there is a tetrad (A,B,C,…

题目:传送门. 题意:平面上有n个点,问是否存在四个点 (A,B,C,D)(A<B,C<D,A≠CorB≠D)使得AB的横纵坐标差的绝对值的和等于CD的横纵坐标差的绝对值的和,n<10^5,点的坐标值m<10^5. 题解:表面上这道题复杂度是O(n^2)会超时的,而实际上这些坐标差绝对值的和最大是2*10^5,所以复杂度不是O(n^2),而是O(min(n^2,m)),这就是著名的鸽笼原理. #include <iostream> #include <cstdio…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 1052    Accepted Submission(s): 582 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he ma…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 1014    Accepted Submission(s): 561 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he mar…

Teacher Bo Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 752    Accepted Submission(s): 412 Problem Description Teacher BoBo is a geography teacher in the school.One day in his class,he mark…

链接:传送门 题意:给出N个点( Xi , Yi ),和点的最远位置M,询问是否有这样的四个点 (A,B,C,D)(A<B,C<D,A≠CorB≠D) ,AB的曼哈顿路径长度等于CD的曼哈顿路径长度 思路: N,M < 10^5 ,如果不仔细想的话可能会误认为复杂度为O( N^2 ),但是M最大是 10^5,也就是说所有的曼哈顿路径最长不会超过 2*10^5,当N > M,枚举超过 2M 时必定能找到一组解,所以直接暴力就ok了,所以这道题的复杂度应该是 O ( min(2M ,…

Saving HDU Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Total Submission(s): 7194    Accepted Submission(s): 3345 Problem Description 话说上回讲到海东集团面临内外交困,公司的元老也只剩下XHD夫妇二人了.显然,作为多年拼搏的商人,XHD不会坐以待毙的.  一天,当他正在苦思冥想解困良策的…

http://acm.hdu.edu.cn/showproblem.php?pid=3037 Lucas定理模板. 现在才写,noip滚粗前兆QAQ #include<cstdio> #include<cstring> #include<algorithm> using namespace std; typedef long long ll; int jc[100003]; int p; int ipow(int x, int b) { ll t = 1, w = x;…