题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=1213 Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at least. You have to notice that not all the friends know each other,…
本文参考了:洛谷p2024题解 题目描述 动物王国中有三类动物 A,B,C,这三类动物的食物链构成了有趣的环形.A 吃 B,B 吃 C,C 吃 A. 现有 N 个动物,以 1 - N 编号.每个动物都是 A,B,C 中的一种,但是我们并不知道 它到底是哪一种. 有人用两种说法对这 N 个动物所构成的食物链关系进行描述: 第一种说法是“1 X Y”,表示 X 和 Y 是同类. 第二种说法是“2 X Y”,表示 X 吃 Y . 此人对 N 个动物,用上述两种说法,一句接一句地说出 K 句话,这 K…
How Many Tables Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Problem Description Today is Ignatius' birthday. He invites a lot of friends. Now it's dinner time. Ignatius wants to know how many tables he needs at…
畅通工程 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) http://acm.hdu.edu.cn/showproblem.php?pid=1232 Problem Description 某省调查城镇交通状况,得到现有城镇道路统计表,表中列出了每条道路直接连通的城镇.省政府"畅通工程"的目标是使全省任何两个城镇间都可以实现交通(但不一定有直接的道路相连,只要互相间…
The Suspects Time Limit: 1000MS Memory Limit: 20000KTotal Submissions: 36817 Accepted: 17860 Description Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To min…
畅通工程 Time Limit: 4000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 38471 Accepted Submission(s): 20404 Problem Description 某省调查城镇交通状况,得到现有城镇道路统计表,表中列出了每条道路直接连通的城镇.省政府“畅通工程”的目标是使全省任何两个城镇间都可以实现交通(但不一定有直接的道路相…
求连通分量 Sample Input2 //T5 3 //n m1 2// u v2 34 5 5 12 5 Sample Output24 # include <iostream> # include <cstdio> # include <cstring> # include <algorithm> # include <cmath> # include <queue> # define LL long long using na…
链接 https://www.luogu.org/problemnew/show/P1551 代码 #include<bits/stdc++.h> using namespace std; #define ll long long const int maxn=1e5; int par[maxn]; int rank1[maxn]; void f(int n) //初始化 { ;i<n;i++) { par[i]=i; rank1[i]=; } } int find(int x) { i…
P2978 [USACO10JAN]下午茶时间Tea Time 题目描述 N (1 <= N <= 1000) cows, conveniently numbered 1..N all attend a tea time every day. M (1 <= M <= 2,000) unique pairs of those cows have already met before the first tea time. Pair i of these cows who have…
转自:http://blog.csdn.net/shahdza/article/details/7779230 [HDU]1213 How Many Tables 基础并查集★1272 小希的迷宫 基础并查集★1325&&poj1308 Is It A Tree? 基础并查集★1856 More is better 基础并查集★1102 Constructing Roads 基础最小生成树★1232 畅通工程 基础并查集★2120 Ice_cream's world I 基础并查集★212…
G - Brain Network (easy) Time Limit:2000MS Memory Limit:262144KB 64bit IO Format:%I64d & %I64u CodeForces 690C1 Description One particularly well-known fact about zombies is that they move and think terribly slowly. While we still don't know…
并查集 PAT (Advanced Level) Practice 并查集 相关题 <算法笔记> 重点摘要 1034 Head of a Gang (30) 1107 Social Clusters (30) 1118 Birds in Forest (25) <算法笔记> 9.6 并查集 重点摘要 1. 定义 father[i] 表示元素 i的父结点 father[i] = i 表示元素 i 为该集合根结点 每个集合只存在一个根结点,且其作为所属集合的标识 int father[…
题目描述 简单的并查集模板 输入描述 第一行包含两个整数N.M,表示共有N个元素和M个操作. 接下来M行,每行包含三个整数Zi.Xi.Yi 当Zi=1时,将Xi与Yi所在的集合合并 当Zi=2时,输出Xi与Yi是否在同一集合内,是的话输出Y:否则话输出N. 分析 简单的模板,解释留到算法微解读 AC代码 #include <bits/stdc++.h> using namespace std; int n,m; int fa[10000+5]; inline int read(){ int X…
The Suspects Time Limit: 1000MS Memory Limit: 20000K Total Submissions: 20596 Accepted: 9998 Description Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003.…
The Suspects Time Limit: 1000MS Memory Limit: 20000K Total Submissions: 37090 Accepted: 17980 Description Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. T…
Description Severe acute respiratory syndrome (SARS), an atypical pneumonia of unknown aetiology, was recognized as a global threat in mid-March 2003. To minimize transmission to others, the best strategy is to separate the suspects from others. In t…
