PAT 1050 String Subtraction

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PAT 1050 String Subtraction

1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However,…

pat 1050 String Subtraction（20 分）

1050 String Subtraction(20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it…

PAT 解题报告 1050. String Subtraction (20)

1050. String Subtraction (20) Given two strings S1 and S2, S = S1 - S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1 - S2 for any given strings. However, it might not be that…

PAT 甲级 1050 String Subtraction (20 分) （简单送分,getline(cin,s)的使用）

1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However,…

PAT甲级——1050 String Subtraction

1050 String Subtraction Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might…

1050 String Subtraction （20 分）

1050 String Subtraction (20 分) Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2from S1. Your task is simply to calculate S1−S2 for any given strings. However, it…

PAT (Advanced Level) 1050. String Subtraction (20)

简单题. #include<iostream> #include<cstring> #include<cmath> #include<algorithm> #include<cstdio> #include<map> #include<queue> #include<string> #include<vector> using namespace std; +; char t[maxn]; char…

PAT甲题题解-1050. String Subtraction (20)-水题

#include <iostream> #include <cstdio> #include <string.h> #include <algorithm> using namespace std; /* 水题,注意字符范围是整个ASCII编码即可. */ ; int vis[maxn]; +]; +]; int main() { gets(s1); //getchar(); gets(s2); int len1=strlen(s1); int len2=s…

PAT 甲级 1050 String Subtraction

https://pintia.cn/problem-sets/994805342720868352/problems/994805429018673152 Given two strings S~1~ and S~2~, S = S~1~ - S~2~ is defined to be the remaining string after taking all the characters in S~2~ from S~1~. Your task is simply to calculate S…

PAT Advanced 1050 String Subtraction (20 分)

Given two strings S1 and S2, S=S1−S2 is defined to be the remaining string after taking all the characters in S2 from S1. Your task is simply to calculate S1−S2 for any given strings. However, it might not be that simple to do…