题目: In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships.  You have a transportation company there. Some routes are opened for passengers. Each route is…

转载请注明出处:http://blog.csdn.net/u012860063 题目链接:pid=4280">http://acm.hdu.edu.cn/showproblem.php?pid=4280 Problem Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the is…

题意:有N个岛屿,M条路线,每条路都连接两个岛屿,并且每条路都有一个最大承载人数,现在想知道从最西边的岛到最东面的岛最多能有多少人过去(最西面和最东面的岛屿只有一个). 分析:可以比较明显的看出来是一个最大流的问题,而且源点汇点也都给出了,可以用最基本的dinic解决,不过注意一些优化,都则会tle的,下面是dinic AC代码 ====================================================================================…

HDU 4280 Island Transport(网络流,最大流) Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some route…

Island Transport Time Limit: 10000ms Memory Limit: 65536KB This problem will be judged on HDU. Original ID: 4280 64-bit integer IO format: %I64d      Java class name: Main In the vast waters far far away, there are many islands. People are living on…

Island Transport http://acm.hdu.edu.cn/showproblem.php?pid=4280 Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 13032    Accepted Submission(s): 4097 Problem Description In the vast waters far…

Island Transport Problem Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes are open…

Island Transport Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 13187    Accepted Submission(s): 4156 题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4280 Description: In the vast waters far f…

题目链接:https://vjudge.net/problem/HDU-4280 Island Transport Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 9945    Accepted Submission(s): 3214 Problem Description In the vast waters far far aw…

Island Transport Time Limit: 20000/10000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Total Submission(s): 6217    Accepted Submission(s): 1965 Problem Description In the vast waters far far away, there are many islands. People are l…

Island Transport Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes are opened for p…

Problem Description In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes are opened for passengers…

链接: http://acm.hdu.edu.cn/showproblem.php?pid=4280 源点是West, 汇点是East, 用Dinic带入求就好了 代码:要用c++提交 #pragma comment(linker, "/STACK:102400000,102400000") ///手动开大栈区 #include<cstdio> #include<cstring> #include<iostream> #include<algo…

In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes are opened for passengers. Each route is a st…

链接: https://vjudge.net/problem/HDU-4280 题意: In the vast waters far far away, there are many islands. People are living on the islands, and all the transport among the islands relies on the ships. You have a transportation company there. Some routes a…

http://acm.hdu.edu.cn/showproblem.php?pid=4280 题意:在最西边的点走到最东边的点最大容量. 思路:ISAP模板题,Dinic过不了. #include <cstdio> #include <algorithm> #include <iostream> #include <cstring> #include <string> #include <cmath> #include <que…

题意:给你一个字符串,和每个位置可能的字符(没有就可以放任意字符)要求一个排列使得每个位置的字符在可能的字符中,求字典序最小的那个 题解:很容易判断有没有解,建6个点表示从a-f,和源点连边,容量为原串字符出现次数,再建64个点表示给定的位置的每一个状态,和汇点连边,容量为出现次数,如果a-f某个字符在状态中出现过,再把a-f和状态连边,容量inf,但是这只能求可行解,并不是字典序最小, 我们枚举每个位置该放哪个字符(a-f),假设该位置是pos,枚举的字符是x,该位置可能字符的状态是st,现在…

HDU 4280:http://acm.hdu.edu.cn/showproblem.php?pid=4280 题意: 比较裸的最大流题目,就是这是个无向图,并且比较卡时间. 思路: 是这样的,由于是无向图,所以addedge 的反边容量直接设为原始流量.然后还可以优化搜索的方向,bfs可以从t到s跑,dfs可以从s到t跑,这样快. //#pragma GCC optimize(3) //#pragma comment(linker, "/STACK:102400000,102400000&qu…

题目链接 可以说是真的把时间卡爆了,不断的修改了好多次之后才A了,一直T一直T,哭了…… 可以说是很练时间优化了,不断的改,不断的提交,最后竟然是改了Dinic中的BFS()中,我们一旦搜索到了T之后就是直接break掉,就可以过了.还有一个优化就是在Dinic上面需要加当前弧优化操作才可以,另外不知道改出来的手动队列到最后有没有派上用处. #pragma comment(linker, "/STACK:1024000000,1024000000") #include <iost…

题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4280 题意:有n个岛屿,m条无向路,每个路给出最大允许的客流量,求从最西的那个岛屿最多能运用多少乘客到最东的那个岛屿 题解:最大流的裸题.输入记得找到最西和最东的岛屿,以及注意是双向边..这题用的sap. 代码: #include<iostream> #include<cstdio> #include<cstring> #include<cmath> #incl…

ISAP求最大流模板 #include<cstdio> #include<cstring> #include<algorithm> #include<iostream> #include<queue> using namespace std; ; const int inf=1e9; struct node { int from,to,next; int cap; }edge[maxn*]; int tol; int head[maxn]; in…

题意: 求最大流 思路: \(1e5\)条边,偷了一个超长的\(HLPP\)板子.复杂度\(n^2 \sqrt{m}\).但通常在随机情况下并没有isap快. 板子: template<class T = int> struct HLPP{ const int MAXN = 1e5 + 5; const T INF = 0x3f3f3f3f; struct edge{ int to, rev; T f; }; vector<edge> adj[maxn]; deque<int…

A - ACM Computer Factory 题目描述:某个工厂可以利用P个部件做一台电脑,有N个加工用的机器,但是每一个机器需要特定的部分才能加工,给你P与N,然后是N行描述机器的最大同时加工数目Q,输入部件要求和输出部件状态,问单位时间内最多可以做多少台机器,再输出运输路线和每一条路线上的待加工机器个数 解题思路:由于机器有最大流量,又是一个点,因此要拆点成一条边,然后构建源点S和汇点T,若一个机器对输入没有任何要求(只有2或0),则从S连一条边到该机器,流量为Q:若一个机器的输出全为1…

A - ACM Computer Factory POJ - 3436 As you know, all the computers used for ACM contests must be identical, so the participants compete on equal terms. That is why all these computers are historically produced at the same factory. Every ACM computer…

        ID Origin Title   34 / 81 Problem A POJ 3436 ACM Computer Factory   92 / 195 Problem B POJ 3281 Dining   55 / 148 Problem C POJ 1087 A Plug for UNIX   59 / 111 Problem D POJ 2195 Going Home   44 / 132 Problem E POJ 2516 Minimum Cost   35 / 72…

首先是几份模版 最大流:虽然EK很慢但是优势就是短.求最小割的时候可以根据增广时的a数组来判断哪些边是割边.然而SAP的最大流版我只会套版,并不知道该如何找到这个割边.在尝试的时候发现了一些问题.所以暂且搁下.这个问题目前先就EK把 struct Edge { int u,v,next; LL cap,flow; }edge[MAXM]; int head[MAXN],tot; void add_edge(int u,int v,LL cap) { edge[tot].u = u; edge[t…

比赛链接: http://vjudge.net/contest/view.action?cid=47644#overview 比赛来源: 2012 ACM/ICPC Asia Regional Tianjin Online 果然我还是很受外界影响啊~~~这场打得好烂~~~ 155 / 175 Problem A HDU 4278 Faulty Odometer (水题, 简单的数位DP) 155 / 345 Problem B HDU 4279 Number  (打表找规律)   86 / 41…

KUANGBIN带你飞 全专题整理 https://www.cnblogs.com/slzk/articles/7402292.html 专题一 简单搜索 POJ 1321 棋盘问题    //2019.3.18 POJ 2251 Dungeon Master POJ 3278 Catch That Cow  //4.8 POJ 3279 Fliptile POJ 1426 Find The Multiple  //4.8 POJ 3126 Prime Path POJ 3087 Shuffle…

[kuangbin带你飞]专题1-23 专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil Deposit…

专题一 简单搜索 POJ 1321 棋盘问题POJ 2251 Dungeon MasterPOJ 3278 Catch That CowPOJ 3279 FliptilePOJ 1426 Find The MultiplePOJ 3126 Prime PathPOJ 3087 Shuffle'm UpPOJ 3414 PotsFZU 2150 Fire GameUVA 11624 Fire!POJ 3984 迷宫问题HDU 1241 Oil DepositsHDU 1495 非常可乐HDU 26…