A very hard Aoshu problem                           Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than o…

枚举等号的位置,然后暴力搜索一波 这个题本身不难,但它是我第一次使用对拍程序来查找错误,值得纪念. #include<cstdio> #include<string.h> #include<map> #include<algorithm> #define inf 0x3f3f3f3f ; using namespace std; typedef pair<int,int> P; int len,d,b,c,ans; ]; map<P,int…

A very hard Aoshu problem Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary mathematics for primary school students. Teacher Liu is an Aoshu teacher. He just comes out with a pro…

题目连接:http://acm.hdu.edu.cn/showproblem.php?pid=4403 A very hard Aoshu problem Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1080    Accepted Submission(s): 742 Problem Description Aoshu is ver…

Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDE In the equation above, a letter stands for…

Description Math Olympiad is called “Aoshu” in China. Aoshu is very popular in elementary schools. Nowadays, Aoshu is getting more and more difficult. Here is a classic Aoshu problem: ABBDE __ ABCCC = BDBDEIn the equation above, a letter stands for a…

题意:题意:给你3个字符串s1,s2,s3;要求对三个字符串中的字符赋值(同样的字符串进行同样的数字替换), 替换后的三个数进行四则运算要满足左边等于右边.求有几种解法. Sample Input 2 A A A BCD BCD B   Sample Output 5 72 eg:ABBDE   ABCCC   BDBDE :令 A = 1, B = 2, C = 0, D = 4, E = 5 12245 + 12000 = 24245: 注意没有前导零! ! #include<stdio.h…

A very hard Aoshu proble Problem Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary mathematics for primary school students. Teacher Liu is an Aoshu teacher. He just comes out with a prob…

C. NP-Hard Problem time limit per test:2 seconds memory limit per test:256 megabytes input:standard input output:standard output Recently, Pari and Arya did some research about NP-Hard problems and they found the minimum vertex cover problem very int…

题目链接:https://vjudge.net/problem/UVALive-5107 题目大意:用ABCDE代表不同的数字,给出形如ABBDE___ABCCC = BDBDE的东西: 空格里面可以填入+-*/的运算符,给字母赋予不同的值,问有多少种情况使得 等式成立. 题目分析: 可以直接用大模拟+暴力求解,注意对于重复情况的判重. 给出代码: #include <iostream> #include <set> #include <algorithm> #incl…

Problem UVA524-Prime Ring Problem Accept:6782  Submit:43814 Time Limit: 3000 mSec  Problem Description A ring is composed of n (even number) circles as shown in diagram. Put natural numbers 1,2,...,n into each circle separately, and the sum of number…

//给一个长度为大于2小于15的字符串 //在当中间加'+'或'='使得其成为一个等式的方法的个数 //枚举等号位置.暴力搜索加号加的位置 #include<cstdio> #include<cstring> #include<iostream> using namespace std ; const int maxn = 20; typedef __int64 ll ; int ans; int a[maxn] ,len_a; int b[maxn] , len_b…

HASH+暴力. /* 4403 */ #include <iostream> #include <cstdio> #include <cstring> #include <cstdlib> #include <map> using namespace std; #define MAXN 55 map<]; char s[MAXN]; int get(int b, int e) { ; for (int i=b; i<e; ++i)…

暴力$dfs$. 先看数据范围,字符串最长只有$15$,也就是说枚举每个字符后面是否放置“$+$”号的复杂度为${2^{15}}$. 每次枚举到一种情况,看哪些位置能放“$=$”号,每个位置都试一下,然后判断一下是否可行. 最坏复杂度$O({2^{15}}*{15^2})$,事实上是达不到最坏复杂度的. #pragma comment(linker, "/STACK:1024000000,1024000000") #include<cstdio> #include<c…

http://acm.hdu.edu.cn/showproblem.php?pid=4403 题意: 给出一串数字,在里面添加一个等号和多个+号,使得等式成立,问有多少种不同的式子. 思路: 数据量比较小,直接dfs爆搜答案即可. #include<iostream> #include<cstdio> #include<cstring> #include<algorithm> #include<map> using namespace std;…

题意:给你一个数字字符串.问在字符串中间加'='.'+'使得'='左右两边相等. 1212  : 1+2=1+2,   12=12. 12345666 : 12+3+45+6=66.  1+2+3+4+56=66: #include<stdio.h> #include<string.h> #include<string> #include<map> #include<stack> #include<math.h> #include&l…

A very hard Aoshu problem Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4403 Description Aoshu is very popular among primary school students. It is mathematics, but much harder than ordinary m…

题目链接:A hard Aoshu Problem DES:给三个字符串,包含的字符是A-E范围内的.长度都不超过8.每个字符可以而且只可以匹配一个数字.两个字符不能匹配相同的数字.前两个式子之间可以有+-*/四中关系.然后=第三个式子.问.会有多少种关系式. #include<stdio.h> #include<string.h> #include<iostream> using namespace std; ][]; ], b[], c[]; // 字符转换成数字后…

比赛链接: http://vjudge.net/contest/view.action?cid=47642#overview 题目来源: 2012 ACM/ICPC Asia Regional Jinhua Online     ID Origin Title   18 / 70 Problem A HDU 4400 Mines  (搜索, ★★★☆☆)   1 / 1 Problem B HDU 4401 Battery (数学, ★★☆☆☆ )    2 / 2 Problem C HDU…

杭电ACM分类: 1001 整数求和 水题1002 C语言实验题——两个数比较 水题1003 1.2.3.4.5... 简单题1004 渊子赛马 排序+贪心的方法归并1005 Hero In Maze 广度搜索1006 Redraiment猜想 数论:容斥定理1007 童年生活二三事 递推题1008 University 简单hash1009 目标柏林 简单模拟题1010 Rails 模拟题(堆栈)1011 Box of Bricks 简单题1012 IMMEDIATE DECODABILITY…

A hard Aoshu Problem http://acm.hdu.edu.cn/showproblem.php?pid=3699 用深搜写排列,除法要注意,还有不能有前导零.当然可以5个for,但是如果有很多个,dfs还是好的. #include<cstdio> #include<cstring> #include<iostream> #include<map> #define mt(a,b) memset(a,b,sizeof(a)) using n…

转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…

本次是弱校题解-比赛链接 备用链接 题目还是比较基础,比较简单.认真补题,学会学习. A -人见人爱A^B 题解: 求 A的B次方,我们可以用循环进行累乘操作,进而计算出次方.因为题目要求只需要求出最后三位,所以每次对 1000 求余数,最后输出即可. #include<stdio.h> #include<string.h> #include<stdlib.h> #include<math.h> int main() { int n,m; while(sca…

Palindromic characteristics of string s with length |s| is a sequence of |s| integers, where k-th number is the total number of non-empty substrings of s which are k-palindromes. A string is 1-palindrome if and only if it reads the same backward as f…

Problem L: 搜索基础之马走日 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 134  Solved: 91[Submit][Status][Web Board] Description 马在中国象棋以日字形规则移动. 请编写一段程序,给定n*m大小的棋盘,以及马的初始位置(x,y),要求不能重复经过棋盘上的同一个点,计算马可以有多少途径遍历棋盘上的所有点. Input 第一行为整数T(T < 10),表示测试数据组数.每一组测试数据包含一…

Problem K: 搜索基础之棋盘问题 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 92  Solved: 53[Submit][Status][Web Board] Description 在一个给定形状的棋盘(形状可能是不规则的)上面摆放棋子,棋子没有区别.要求摆放时任意的两个棋子不能放在棋盘中的同一行或者同一列,请编程求解对于给定形状和大小的棋盘,摆放k个棋子的所有可行的摆放方案C. Input 输入含有多组测试数据.每组数据的第一行是两…

Problem J: 搜索基础之红与黑 Time Limit: 1 Sec  Memory Limit: 128 MBSubmit: 170  Solved: 100[Submit][Status][Web Board] Description 有一间长方形的房子,地上铺了白色.黑色两种颜色的正方形瓷砖.你站在其中一块黑色的瓷砖上,只能向相邻的黑色瓷砖移动.请写一个程序,计算你总共能够到达多少块黑色的瓷砖. Input 包括多个数据集合.每个数据集合的第一行是两个整数W和H,分别表示x方向和y方…

Partition problem 题目传送门 解题思路 假设当前两队的对抗值为s,如果把红队中的一个人a分配到白队,s+= a对红队中所有人的对抗值,s-= a对白队中所有人的对抗值.所以我们可以先假设所有人都在红队中,把人一个一个分配到白队中,枚举所有的情况求最大值. 然后继续剪枝: 1.我们可以让1是固定在白队. 2.在搜索的过程中让序号递增,以此来避免重复枚举. 3.保证剩下的的人数足够选择,不够的必然不行. 代码如下 #include <bits/stdc++.h> #define…

Prime Ring Problem Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 12105    Accepted Submission(s): 5497 Problem Description A ring is compose of n circles as shown in diagram. Put natural numb…

发现自己搜索真的很弱,也许做题太少了吧.代码大部分是参考别人的,=_=|| 题意: 给出一个phi(n),求最小的n 分析: 回顾一下欧拉函数的公式:,注意这里的Pi是互不相同的素数,所以后面搜索的时候要进行标记. 先找出所有的素数p,满足(p - 1)整除题目中所给的phi(n) 然后暴搜.. 素数打表打到1e4就够了,如果最后剩下一个大素数单独进行判断. #include <cstdio> #include <cmath> #include <cstring> #i…