Sum Time Limit:1000MS Memory Limit:131072KB 64bit IO Format:%I64d & %I64u Submit Status Practice HDU 4704 Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input file consists of multiple test cases. 题意…
题目传送:http://acm.hdu.edu.cn/showproblem.php?pid=4704 Problem Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input file consists of multiple test cases. 题意是输入一个N,求N被分成1个数的结果+被分成2个数的结果+...+被分成N个数的结果,N很大 1.隔板原…
Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 647 Accepted Submission(s): 320 Problem Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input…
Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 94 Accepted Submission(s): 41 Problem Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input fil…
Sum Time Limit : 2000/1000ms (Java/Other) Memory Limit : 131072/131072K (Java/Other) Total Submission(s) : 78 Accepted Submission(s) : 30 Font: Times New Roman | Verdana | Georgia Font Size: ← → Problem Description Sample Input 2 Sample Output 2…
Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 3980 Accepted Submission(s): 1620 Problem Description Sample Input 2 Sample Output 2 Hint 1. For N = 2, S(1) = S(2) = 1. 2. The input…
HDOJ(HDU).1258 Sum It Up (DFS) [从零开始DFS(6)] 点我挑战题目 从零开始DFS HDOJ.1342 Lotto [从零开始DFS(0)] - DFS思想与框架/双重DFS HDOJ.1010 Tempter of the Bone [从零开始DFS(1)] -DFS四向搜索/奇偶剪枝 HDOJ(HDU).1015 Safecracker [从零开始DFS(2)] -DFS四向搜索变种 HDOJ(HDU).1016 Prime Ring Problem (DF…
sum 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5776 Description Given a sequence, you're asked whether there exists a consecutive subsequence whose sum is divisible by m. output YES, otherwise output NO Input The first line of the input has an i…
Sum Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://acm.hdu.edu.cn/showproblem.php?pid=5586 Description There is a number sequence A1,A2....An,you can select a interval [l,r] or not,all the numbers Ai(l≤i≤r) will become f(Ai).f(x)=(1890x+143)mod1…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=5586 Sum Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 677 Accepted Submission(s): 358 Problem Description There is a number sequence A1,A2...…
题目链接:http://acm.hdu.edu.cn/showproblem.php?pid=4432 代码: #include<cstdio> #include<cstring> #include<iostream> #include<algorithm> using namespace std; int sum; int n,k; int tranfer(int num) { ; ) { int a = num%k; num = num/k; ret +…
http://acm.hdu.edu.cn/showproblem.php?pid=4407 题意:给定初始n个数1..n,两个操作,①1 x y p 询问第x个数到第y个数中与p互质的数的和; ②:2 x y 把第x个数变成y: 思路: 把p分解质因子,然后找出(1,pos)内与p不互质的,然后用的减去就是互质的和,第二个操作用到map映射,记录在那个位置改变之后的数. #include <cstdio> #include <cstring> #include <map…