EXGCD的模板水题 RSA算法给你两个大素数p,q定义n=pq,F(n)=(p-1)(q-1) 找一个数e 使得(e⊥F(n)) 实际题目会给你e,p,q计算d,$de \mod F(n) = 1$然后解密的值为$c_{i}^d \mod n$,转换成char输出 用EXGCD求出d就好了 /** @Date : 2017-09-07 22:17:00 * @FileName: HDU 1211 EXGCD.cpp * @Platform: Windows * @Author : Lwelet…

// 表示题目意思我是理解了蛮久 英语太水了 //首先这是解密公式 m=c^d mod n// 给你 p q e 然后 n=p*q fn=(p-1)*(q-1)// 给你 e,根据公式 e*d mod fn =1 求出 d // 然后有 L个数据要解密// 算法:// 扩展欧几里得 :求 d// 快速幂运算 :解密#include <iostream> #include <algorithm> #include <queue> #include <vector&g…

RSA Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 2353    Accepted Submission(s): 1677 Problem Description RSA is one of the most powerful methods to encrypt data. The RSA algorithm is describ…

RSA Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1243    Accepted Submission(s): 901 Problem Description RSA is one of the most powerful methods to encrypt data. The RSA algorithm is describe…

水.模拟即可.使用EXGCD求逆元 #include <iostream> #include <cstdio> #include <cstring> #include <algorithm> #define LL __int64 using namespace std; LL p,q,e,n,f,d; void exgcd(LL a,LL b,LL &x,LL &y){ if(b==0){ x=1; y=0; return ; } exgcd…

HDU 模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 1049 1050 1057 1062 1063 1064 1070 1073 1075 1082 1083 1084 1088 1106 1107 1113 1117 1119 1128 1129 1144 1148 1157 1161 1170 1172 1177 1197 1200 1201…

转载来自:http://www.cppblog.com/acronix/archive/2010/09/24/127536.aspx 分类一: 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029.1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093.1094.1095.1096.1097.1098.1106.1108.1157…

模拟题, 枚举1002 1004 1013 1015 1017 1020 1022 1029 1031 1033 1034 1035 1036 1037 1039 1042 1047 1048 1049 1050 1057 1062 1063 1064 1070 1073 1075 1082 1083 1084 1088 1106 1107 1113 1117 1119 1128 1129 1144 1148 1157 1161 1170 1172 1177 1197 1200 1201 120…

转载:from http://blog.csdn.net/qq_28236309/article/details/47818349 基础题:1000.1001.1004.1005.1008.1012.1013.1014.1017.1019.1021.1028.1029. 1032.1037.1040.1048.1056.1058.1061.1070.1076.1089.1090.1091.1092.1093. 1094.1095.1096.1097.1098.1106.1108.1157.116…

A/B Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 7310    Accepted Submission(s): 5798 Problem Description 要求(A/B)%9973,但由于A很大,我们只给出n(n=A%9973)(我们给定的A必能被B整除,且gcd(B,9973) = 1).   Input 数据的第一行是一…