The gray code is a binary numeral system where two successive values differ in only one bit. Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0. Ex…

The gray code is a binary numeral system where two successive values differ in only one bit. Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0. Fo…

The gray code is a binary numeral system where two successive values differ in only one bit. Given a non-negative integer n representing the total number of bits in the code, print the sequence of gray code. A gray code sequence must begin with 0. Fo…

格雷码 the n-1 bit code, with 0 prepended to each word, followd by the n-1 bit code in reverse order, with 1 prepended to each word. public class GrayCode{ public static void gray(int n, String prefix) { ) System.out.println(prefix); else { gray(n-,pref…

The gray code is a binary numeral system where two successive values differ in only one bit. Given a non-negative integer n representing the total number of bits in the code, find the sequence of gray code. A gray code sequence must begin with 0 and…

基本概念 格雷码是一种准权码,具有一种反射特性和循环特性的单步自补码,它的循环.单步特性消除了随机取数时出现重大误差的可能,它的反射.自补特性使得求反非常方便.格雷码属于可靠性编码,是一种错误最小化的编码方式. 自然二进制码可以直接由数/模转换器转换成模拟信号,但是在某些情况下,例如从十进制的3转换到4的二进制时,每一位都要变.3的二进制位:,而4的二进制位:100,所以这就会使数字电路产生很大的尖峰电流脉冲.而格雷码则没有这一缺点,它是一种数字排序系统,其中的所有相邻整数在它们的数字表示中只有…

原题地址 二进制码 -> 格雷码:从最右边起,依次与左边相邻位异或,最左边一位不变.例如: 二进制: 1 0 0 1 1 1 0 |\|\|\|\|\|\| 格雷码: 1 1 0 1 0 0 1 从二进制到格雷码有一个残暴公式: a ^ (a << 1) 格雷码 -> 二进制码:从左边第二位开始,依次与左边相邻已经解码位异或,最左边一位不变.例如: 格雷码: 1 1 0 1 0 0 1 \| | | | | | 1 | | | | | 1 0\| | | | | 1 0 | | |…

题意:给一个二进制数(包含3种符号:'0'  '1'  '?'  ,问号可随意 ),要求将其转成格雷码,给一个序列a,若转成的格雷码第i位为1,则得分+a[i].求填充问号使得得分最多. 思路:如果了解格雷码的转换,相信能很快看出一些端倪.偷别人的图: 分析一下:所给的二进制数要转成格雷码,只与所给二进制有关.即不需要利用已经某些转换好的格雷码字. 接下来分析5个位的串 : (1)00?00 仅有1个问号,只会与后面那些连续且非问号的串转成格雷码有关 (2)00??0 有连续的1个问号,这才需要…

Question 89. Gray Code Solution 思路: n = 0 0 n = 1 0 1 n = 2 00 01 10 11 n = 3 000 001 010 011 100 101 110 111 Java实现: public List<Integer> grayCode(int n) { List<Integer> list = new ArrayList<>(); grayCode(n, 0, list); return list; } voi…

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