hdu 5818 (优先队列) Joint Stacks】的更多相关文章

题目:这里 题意: 两个类似于栈的列表,栈a和栈b,n个操作,push a x表示把数x放进a栈的栈底,pop b 表示将栈b的栈顶元素取出输出,并释放这个栈顶元素,merge a b表示把后面的那个 栈里的元素全部压进前面的那个栈里面,并且压入后前面的栈的所有元素按其进栈顺序排列然后后面的栈变为了空. push和pop操作都还好,就是优先队列或者栈的操作,主要是merge操作,如果啊按照题目来模拟每次将后面的栈元素取出放入前面的栈,可能会超时,而超时的主要因素是每次都将 元素多的栈压入了元素少…
http://acm.hdu.edu.cn/showproblem.php?pid=5818 Joint Stacks Problem Description   A stack is a data structure in which all insertions and deletions of entries are made at one end, called the "top" of the stack. The last entry which is inserted i…
Joint Stacks 题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=5818 Description A stack is a data structure in which all insertions and deletions of entries are made at one end, called the "top" of the stack. The last entry which is inserted is th…
Joint Stacks Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1819    Accepted Submission(s): 819 Problem Description A stack is a data structure in which all insertions and deletions of entries…
HDU 5818 Joint Stacks(联合栈) Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others) Description 题目描述 A stack is a data structure in which all insertions and deletions of entries are made at one end, called the "top" of…
Joint Stacks Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 828    Accepted Submission(s): 403 Problem Description A stack is a data structure in which all insertions and deletions of entries a…
Joint StacksCrawling in process... Crawling failed Time Limit:4000MS     Memory Limit:65536KB     64bit IO Format:%I64d & %I64u Submit Status Practice HDU 5818 uDebug Description   Input   Output   Sample Input   Sample Output   Hint   Description A…
HDU  5818 Problem Description A stack is a data structure in which all insertions and deletions of entries are made at one end, called the "top" of the stack. The last entry which is inserted is the first one that will be removed. In another wor…
多校7 HDU5818 Joint Stacks 题意:n次操作.模拟栈的操作,合并的以后,每个栈里的元素以入栈顺序排列 思路:开三个栈,并且用到了merge函数 O(n)的复杂度 #include <bits/stdc++.h> using namespace std; #define LL long long const int inf = 0x3f3f3f3f; ; ; #define clc(a,b) memset(a,b,sizeof(a)) ; void fre() {freope…
Joint Stacks                                                                       Time Limit: 8000/4000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)                                                                                    …