UVa 993: Product of digits】的更多相关文章

  Product of digits  For a given non-negative integer number N , find the minimal natural Q such that the product of all digits of Q is equal N . Input The first line of input contains one positive integer number, which is the number of data sets. Ea…
这道题很简单.先将N用2,3,5,7(即10以内的素数)分解因数(需要先特殊判断N不为1),然后将可以合并的因数合并(如2*2合并成4,)这样求得的结果位数会减少,大小肯定会小一些.具体实现见代码. 我的解题代码如下: #include <iostream> #include <cstdio> #include <cstring> #include <cmath> #include <cstdlib> #include <string>…
高精度乘法问题,WA了两次是因为没有考虑结果为0的情况.  Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of…
虽然是错的代码,但是还是想贴出来,最开始WA发现是没有考虑到乘积为0的情况,后来把a*0,0*a,a*0---0(若干个0),0--0(若干个0)*a都考虑进去了:可是还是WA,实在不懂先留在这儿.  Product  The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each…
Product The Problem The problem is to multiply two integers X, Y. (0<=X,Y<10250) The Input The input will consist of a set of pairs of lines. Each line in pair contains one multiplyer. The Output For each input pair of lines the output line should c…
package com.njupt.acm; import java.math.BigInteger; import java.util.Scanner; public class UVA_10106 { public static void main(String[] args) { Scanner scanner = new Scanner (System.in); while(scanner.hasNext()){ BigInteger a = scanner.nextBigInteger…
题意: 给n个数字的序列,C v p 把v位上的数字置成p , S l r代表求区间[l,r]各数字相乘得数的符号,对于每个S输出所得符号(’+‘,’-‘,’0‘) 分析: 开两个数组表示区间负数的个数.0的个数.当数字被改时,更新数组.查询时区间含0符号是0,再根据负数的个数的奇偶判断. #include <map> #include <set> #include <list> #include <cmath> #include <queue>…
/* * URAL_1014.cpp * * Created on: 2013年10月11日 * Author: Administrator */ #include <iostream> #include <cstdio> #include <cmath> #include <algorithm> using namespace std; const int maxn = 11; int a[maxn]; int main() { int n; scanf(…
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题目如下: Given an integer number n, return the difference between the product of its digits and the sum of its digits. Example 1: Input: n = 234 Output: 15 Explanation: Product of digits = 2 * 3 * 4 = 24 Sum of digits = 2 + 3 + 4 = 9 Result = 24 - 9 = 1…