LeetCode91 Decode Ways】的更多相关文章

题目: A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of ways to decode it. For example,Given enco…
一条包含字母 A-Z 的消息通过以下方式进行了编码: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 给定一个只包含数字的非空字符串,请计算解码方法的总数. 示例 1: 输入: "12" 输出: 2 解释: 它可以解码为 "AB"(1 2)或者 "L"(12). 示例 2: 输入: "226" 输出: 3 解释: 它可以解码为 "BZ" (2 26), "VF&q…
A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of ways to decode it. For example,Given encoded…
A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1'B' -> 2...'Z' -> 26Given an encoded message containing digits, determine the total number of ways to decode it. ExampleGiven encoded message 1…
Decode Ways A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of ways to decode it. For example, G…
题目: A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of ways to decode it. For example,Given enco…
https://leetcode.com/problems/decode-ways/ A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of wa…
1 题目 A message containing letters from A-Z is being encoded to numbers using the following mapping: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Given an encoded message containing digits, determine the total number of ways to decode it. For example, Given en…
A message containing letters from A-Z is being encoded to numbers using the following mapping way: 'A' -> 1 'B' -> 2 ... 'Z' -> 26 Beyond that, now the encoded string can also contain the character '*', which can be treated as one of the numbers…
首先回顾一下decode ways I 的做法:链接 分情况讨论 if s[i]=='*' 考虑s[i]单独decode,由于s[i]肯定不会为0,因此我们可以放心的dp+=dp1 再考虑s[i-1]和s[i]decode,如果s[i-1]为*,那么**的组合共有15种(11,12,13.....,21,22..26),注意不是9*9=81种,因为我们是s[i-1]和s[i]一起decode,如果是38这样是大于26的 如果s[i-1]不为*,枚举s[i],组合起来小于26即可 if s[i]!…