Xtreme9.0 - Block Art 线段树】的更多相关文章

Block Art 题目连接: https://www.hackerrank.com/contests/ieeextreme-challenges/challenges/block-art Description The NeoCubist artistic movement has a very distinctive approach to art. It starts with a rectangle which is divided into a number of squares. T…
http://acm.hdu.edu.cn/showproblem.php?pid=5023 Problem Description Corrupt governors always find ways to get dirty money. Paint something, then sell the worthless painting at a high price to someone who wants to bribe him/her on an auction, this seem…
A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 100000/100000 K (Java/Others) Problem Description Corrupt governors always find ways to get dirty money. Paint something, then sell the worthless painting at a…
A Corrupt Mayor's Performance Art Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 100000/100000 K (Java/Others)Total Submission(s): 33    Accepted Submission(s): 11 Problem Description Corrupt governors always find ways to get dirty money. Pa…
Link:  http://acm.hdu.edu.cn/showproblem.php?pid=5023 #include <cstdio> #include <cstring> #include <iostream> #include <algorithm> #include <vector> #include <string> #include <cmath> using namespace std; typedef…
题目大意:给出n条垂直于x轴的线段的数据y1,y2,x,求出有几个三条线段一组的三元组并且他们兩兩能相见的.思路:对y轴建树,将x排序,然后按顺序边询问边擦入,用mark[i][j]表示j往左可以看到i.最后用一个三重循环计算答案.但是注意:0,4,1 和 0,2,2 和 3,4,2这三条线段覆盖的结果是区间0~4通过线段树查找可见线段是两条,其实是3条(2~3可见另一条) 这里可以将y轴×2表示.这样就能解决这样的问题0 1 2 3 4 2~3被覆盖 所以乘2解决 #include<stdio…
转载自:http://blog.csdn.net/qq_18455665/article/details/50989113 前言 首先说说出处: 清华大学 张昆玮(zkw) - ppt <统计的力量> 本文(辣鸡)编辑:BeiYu 写这篇博客的原因:  1.zkw线段树非递归,效率高,代码短  2.网上关于zkw线段树的讲解实在是太少了  3.个人感觉很实用 更新日志 20160327-Part 1(zkw线段树的建立) 20160329-Part 2(单点操作) 20160329-Part…
注意添加到集合中的数是升序的,先将数据读入,再离散化. sum[rt][i]表示此节点的区域位置对5取模为i的数的和,删除一个数则右边的数循环左移一位,添加一个数则右边数循环右移一位,相当于循环左移4位,线段树与树状数组结合,树状数组确定位置. le[rt]表示左移的位数,区间更新懒惰标记 #include <iostream> #include <cstdio> #include<cstdlib> #include<map> #include<alg…
Problem Description In mathematics and computer science, an algorithm describes a set of procedures or instructions that define a procedure. The term has become increasing popular since the advent of cheap and reliable computers. Many companies now e…
题意:给定n个矩形,每个矩形有一种颜色,RGB中的一种.相交的部分可能为RG,RB,GB,RGB,问这n个矩形覆盖的面积中,7种颜色的面积分别为多少 思路:把x轴离散化做扫描线,线段树维护一个扫描区间竖直方向上的各种颜色的长度 刚开始想着直接维护每段区间上7种颜色的长,但是写到删除的时候发现没办法删除, 然后想了半天,发现:需要的只是整个区间的颜色长度信息,所以,对于颜色更新来说,不需要往下传标记,只需要维护上push_up就好了 所以添加删除就简单多了. 用 1 2 4 分别代表R G B 然…