Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

https://leetcode.com/problems/data-stream-as-disjoint-intervals/ Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the da…

问题描述: Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. 解题思路: 这道题是目前最新的题,其实思路很容易找到,难点在于考虑到所有的可能的情形. 首先要确定类必须有一个保存当前结果的集合类List<Interval>,其元素的按Interval的起始值的大小排序,…

Plz take my miserable life T T. 和57 insert interval一样的,只不过insert好多. 可以直接用57的做法一个一个加,然后如果数据大的话,要用tree map,可以迅速找到切入点. Key用的左边界. /** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * I…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals. For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be: [1, 1…

数据流合并成区间,每次新来一个数,表示成一个区间,然后在已经保存的区间中进行二分查找,最后结果有3种,插入头部,尾部,中间,插入头部,不管插入哪里,都判断一下左边和右边是否能和当前的数字接起来,我这样提交了,发现错了,想到之前考虑要不要判重,我感觉是这个问题,然后就是在二分查找的时候,判断一下左右区间是否包含当前的值,包含就直接返回. /** * Definition for an interval. * struct Interval { * int start; * int end; * I…