原题地址https://leetcode.com/problems/single-number-ii/ 题目描述Given an array of integers, every element appears three times except for one. Find that single one. 给出一个整数数组,除了某个元素外所有元素都出现三次.找出仅出现一次的数字. Note: 注意: Your algorithm should have a linear runtime co…
翻译 给定一个整型数组,除了某个元素外其余的均出现了三次. 找出这个元素. 备注: 你的算法应该是线性时间复杂度. 你能够不用额外的空间来实现它吗? 原文 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you…
Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…
Given a non-empty array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?…
Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one. 题意: 在一个整型数组里,只有一个数字出现一次,其他数字都出现了3次,求这个只出现一次的数字(single number). 这真是非常非常有意思的一道题目.如果直接统计各数字出现的次数当然也能达到目的,不过空间复杂度为O(N).能否用O(1)…
传送门 Description Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra me…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 求出数组中只出现一次的数,剩下的都是三次. /** * Created by…
题目描述: Given an array of integers, every element appears three times except for one. Find that single one. 解题思路: 具体参考Detailed explanation and generalization of the bitwise operation method for single numbers 讲的实在是很全面,而且拓展到了一般的情况,膜!! 代码如下: public class…
Given an array of integers, every element appears three times except for one, which appears exactly once. Find that single one.Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? class Solut…
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解题思路一: 一个int的长度是32,因此可以开一个长度为32的数组,表示…
[LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single-number-ii/description/ 题目描述: Given an array of integers, every element appears three times except for one, which appears exactly once. Find that singl…
136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solution { public: int singleNumber(vector<int>& nums) { if(nums.empty()) ; ; ;i < nums.size();i++) res ^= nums[i]; return res; } }; 137. Single N…
Given an array of integers, every element appears twice except for one. Find that single one. 本题利用XOR的特性, X^0 = X, X^X = 0, 并且XOR满足交换律. class Solution(object): def singleNumber(self, nums): """ :type nums: List[int] :rtype: int ""…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路: 这个题是Single Number的进阶版,如果其他的数都出现两次而…
Single Number II Given an array of integers, every element appears threetimes except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 解法一:开辟map记录次数 class So…
问题来源:Single Number II 问题描述:给定一个整数数组,除了一个整数出现一次之外,其余的每一个整数均出现三次,请找出这个出现一次的整数. 大家可能很熟悉另一个题目(Single Number):除了一个数出现一次之外,其余的均出现两次,找到出现一次的数.该问题很简单,大家肯定都知道解法:将所有的数异或,最后的结果即是出现一次的数.用到的知识是A^A=0,两个相同的数异或变为0,然后0^B=B,这样即可找到出现一次的数. 新问题有了变化,出现两次变成出现三次,整个问题的解法就不一样…
Problem Discription: Suppose the array A has n items in which all of the numbers apear 3 times except one. Find the single number. int singleNumber2(int A[], int n) { ; while(n--) { ret ^= A[n]; } return ret; } Related Problem: Suppose the array A ha…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? public class Solution { public int sin…
一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complex…
题目: Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 题解: The code seems tricky and hard…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路:用变量分别存储出现一次.两次.三次的number 出现一次的numbe…
Given an array of integers, every element appears three times except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 自己不会做... 搜答案,发现思路真是太巧妙了 关键:统计每一位上出现1的次…
Given an array of integers, every element appears three times except for one. Find that single one. Note: Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? class Solution(object): def singleNum…
Given an array of integers, every element appears three times except for one. Find that single one. 代码如下: public class Solution { public int singleNumber(int[] nums) { if(nums.length==1||nums.length==2) return nums[0]; Arrays.sort(nums); for(int i=0;…
传送门 Description Given an array of integers, every element appears twice except for one. Find that single one. Note:Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory? 思路 题意:给定一个数组,其中只有一个数没有出现两次,要…
题意: 给定两个32位的整数 N 和 M,以及表示比特位置的 i 与 j .编写一个方法,将 M 插入 N,使得 M 从 N 的第 j 位开始,到第 i 位结束.假定从 j 位到 i 位足以容纳M. 输入:N = 10000101000,M = 10011,i = 2, j = 6 输出:N = 10001001100 解题思路 : 根据题意,我们将问题解决分为三个步骤: (1)将 N 中从 j 到 i 之间的位清零: (2)对 M 进行移位操作,M << i (3)合并 M 与 N . 为…
