题目: Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype shoul…

递归方法运行时间过长.考虑使用动态规划的方法. 代码如下: bool isMatch(string s, string p) { int i,j; int m=s.size(); int n=p.size(); ][n + ]; // b[i][j]表示s[i-1]和p[j-1]的匹配结果 b[][] = true; ; i < m; i++) { b[i + ][] = false; } ; j < n; j++) { b[][j + ] = j > && ][j -…

1 题目 Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype shou…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

Regular Expression Matching Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The f…

https://leetcode.com/problems/regular-expression-matching/ [描述] Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the ent…

# -*- coding: utf8 -*-'''https://oj.leetcode.com/problems/regular-expression-matching/ Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matchin…

# -*- coding: utf8 -*-'''https://oj.leetcode.com/problems/regular-expression-matching/ Implement regular expression matching with support for '.' and '*'. '.' Matches any single character.'*' Matches zero or more of the preceding element. The matchin…

一天一道LeetCode系列 (一)题目 Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The functio…

原题地址:https://oj.leetcode.com/problems/regular-expression-matching/ 题意: Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover…

[Q10] Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input str…

最近代码写的少了,而leetcode一直想做一个python,c/c++解题报告的专题,c/c++一直是我非常喜欢的,c语言编程练习的重要性体现在linux内核编程以及一些大公司算法上机的要求,python主要为了后序转型数据分析和机器学习,所以今天来做一个难度为hard 的简单正则表达式匹配. 做了很多leetcode题目,我们来总结一下套路: 首先一般是检查输入参数是否正确,然后是处理算法的特殊情况,之后就是实现逻辑,最后就是返回值. 当编程成为一种解决问题的习惯,我们就成为了一名纯粹的程序…

Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (n…

10. Regular Expression Matching Hard Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching sh…

Implement regular expression matching with support for '.' and '*'. DP: public class Solution { public boolean isMatch2(String s, String p) { int starCnt = 0; for (int i = 0; i < p.length(); i++) { if (p.charAt(i) == '*') { starCnt++; } } boolean[] s…

Regular Expression Matching Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

题目描述: Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. 解题思路: 这道题如果只考虑“.”的话其实很好完成,所以解题的关键在于处理“*”的情况.以为“*”与前一个字母有关,所以应该整体考虑ch*……的情况.ch*可以匹配0-n个s的字符串…

问题描述: Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. http://i.cnblogs.com/EditPosts.aspx?opt=1 The matching should cover the entire input string…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

称号: Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype shoul…

Problem:Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype s…

Given an input string (s) and a pattern (p), implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (n…

Regular Expression Matching 看到正则就感觉头大,因为正则用好了就很强大.有挑战的才有意思. 其实没有一点思路.循环的话,不能一一对比,匹配模式解释的是之前的字符.那就先遍历模式把. ... 中间 n 次失败的提交 感觉代码逻辑很乱.重新捋一下再动手写. 找几个重点分析一下: Wrong Answer: Input: "aaa" "ab*a*c*a" Output: false Expected: true 调试 aaa ab*a*c*a…

题目 Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should…

我现在在做一个叫<leetbook>的免费开源书项目,力求提供最易懂的中文思路,目前把解题思路都同步更新到gitbook上了,需要的同学可以去看看 书的地址:https://hk029.gitbooks.io/leetbook/ 010. Regular Expression Matching 问题 Implement regular expression matching with support for ‘.’ and ‘*’. ‘.’ Matches any single charact…

Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype should be…

[题目描述] Implement regular expression matching with support for '.' and '*'. '.' Matches any single character. '*' Matches zero or more of the preceding element. The matching should cover the entire input string (not partial). The function prototype sh…