Partition List,拆分链表】的更多相关文章

2.4 Write code to partition a linked list around a value x, such that all nodes less than x come before all nodes greater than or equal to x. LeetCode上的原题,请参见我之前的博客Partition List 划分链表.…
问题描述: Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example,Given 1->4->3…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example,Given 1->4->3->2…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example,Given 1->4->3->2…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Input: head = 1->4->3->2->…
给定一个链表和一个特定值 x,对链表进行分隔,使得所有小于 x 的节点都在大于或等于 x 的节点之前.你应当保留两个分区中每个节点的初始相对位置.例如,给定1->4->3->2->5->2 和 x = 3, 返回1->2->2->4->3->5. 详见:https://leetcode.com/problems/partition-list/description/ Java实现: /** * Definition for singly-link…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. For example,Given 1->4->3->2…
Given a linked list and a value x, partition it such that all nodes less than x come before nodes greater than or equal to x. You should preserve the original relative order of the nodes in each of the two partitions. Example: Input: head = 1->4->3-…
给定一个链表和一个特定值 x,对链表进行分隔,使得所有小于 x 的节点都在大于或等于 x 的节点之前. 你应当保留两个分区中每个节点的初始相对位置. 示例: 输入: head = 1->4->3->2->5->2, x = 3 输出: 1->2->2->4->3->5 class Solution { public: ListNode* partition(ListNode* head, int x) { ListNode* less_head…