select dateadd(dd,number,'2012-1-1') AS date from master..spt_values where type='p' and dateadd(dd,number,'2012-1-1')<='2012-12-30'…

我想得到两个日期之间的所有日期, 例如:输入两个日期,把这两个日期之间的所有日期取出来     如果是:2005-02-01至2005-02-05(同为一个月)     则为:2005-02-01,2005-02-02,2005-02-03,2005-02-04,2005-02-05     如果是:2005-01-29至2005-02-02(不同的月,有31号的月份)   则为:2005-01-29,2005-01-30,2005-01-31,2005-02-01,2005-02-02 <?p…

前言:直接上代码 java 获取两个日期之间的所有日期(年月日) /** * 获取两个日期之间的日期,包括开始结束日期 * @param start 开始日期 * @param end 结束日期 * @return 日期集合 */ private List<Date> getBetweenDates(Date start, Date end) { List<Date> result = new ArrayList<Date>(); Calendar tempStart…

java获取两个日期之间的所有日期   解决方法: 1.核心方法 private List<String> getBetweenDates(String start, String end) { List<String> result = new ArrayList<String>(); try { SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd"); Date start_date =…

需要查两个表之间的差集 首先,想到的是主键直接not in select mailbox_id from co_user where mailbox_id not in (select mailbox_id from core_mailbox); 好吧!这个是可以,但是数据多了的话,想到这个查询的逻辑有点受不住 于是再改为下面的这样: select cu.mailbox_id,cm.mailbox_id from co_user as cu left join core_mailbox as c…

set @i = -1; set @sql = repeat(" select 1 union all",-datediff('2021-01-01','2030-12-31')+1); set @sql = left(@sql,length(@sql)-length(" union all")); set @sql = concat("select date_add('2021-01-01',interval @i:=@i+1 day) as date…

1.返回Date的list private List<Date> getBetweenDates(Date start, Date end) { List<Date> result = new ArrayList<Date>(); Calendar tempStart = Calendar.getInstance(); tempStart.setTime(start); tempStart.add(Calendar.DAY_OF_YEAR, 1); Calendar t…

function getDates($start, $end) { $dt_start = strtotime($start); $dt_end = strtotime($end); do{ echo date('Y-m-d', $dt_start).'</br>; } while(($dt_start += 86400) <= $dt_end); } getDates('2013-02-28','2013-03-02');…

function printDates($start,$end){ $dt_start = strtotime($start); $dt_end = strtotime($end); while ($dt_start<=$dt_end){ echo date('Y-m-d',$dt_start)."<br>"; $dt_start = strtotime('+1 day',$dt_start); } } printDates('2019-1-1','2019-07-0…

SELECT TIMESTAMPDIFF(MINUTE, (DATE_FORMAT('2015-08-12 10:38:00','%Y-%m-%d %H:%i')), (DATE_FORMAT('2015-08-12 10:38:59', '%Y-%m-%d %H:%i')) ) FROM DUAL…