这题根据的Dilworth定理,链的最小个数=反链的最大长度 , 然后就是排序LIS了 链-反链-Dilworth定理 hdu1051 #include <iostream> #include <stdio.h> #include <string.h> #include <math.h> #include <algorithm> #include <string> #include <queue> #include <…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 18745    Accepted Submission(s): 7692 Problem Description There is a pile of n wooden sticks. The length and weight of each stick ar…

题目:http://acm.hdu.edu.cn/showproblem.php?pid=1051 大意:求最少升序序列的个数. #include <cstdio> #include <cstring> #include <algorithm> #define N 5000 + 5 using namespace std; struct node { int x, y; bool operator < (const node& t) const { ret…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 11627    Accepted Submission(s): 4807 Problem Description There is a pile of n wooden sticks. The length and weight of each stick a…

Problem Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to…

题目链接: http://acm.hdu.edu.cn/showproblem.php?pid=1051 题目大意:给你n根木棍的长度和重量.根据要求求出制作该木棍的最短时间.建立第一个木棍需要1分钟,如果接着制作的木棍比这个木棍的长度长(或者相等),重量要重(或者相等),那么接着制作的木棍不需要花费时间!然后如果再继续接着制作,则下一个木棍要比上一个木棍的长度长(或者相等),重量大(或者相等),则这个木棍也不需要花费时间!依次类推,反之,则需要花费一分钟,然后让你求出制作这一批木棍花费的最少的…

Wooden Sticks Problem Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for…

Wooden Sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 26095    Accepted Submission(s): 10554 Problem Description There is a pile of n wooden sticks. The length and weight of each stick a…

Wooden Sticks Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Status Practice _ Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be process…

#include<iostream> #include<algorithm> using namespace std; struct SIZE { int l; int w; }sticks[5005]; int flag[5005]; bool cmp(const SIZE &a,const SIZE &b)//这里是排序! {//写排序函数的时候要特别的小心! //if(a.w!=b.w)//这里写错了,这里表示如果重量不等,按照长度排,如果重量相等,则按照重量…

Problem Description There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to…

嘤嘤嘤,实习半年多的小蒟蒻的第一篇博客(题解) 英文的: There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the m…

题目大意:有n根木棍(n<5000),每根木棍有一个长度l和重量w(l,w<10000),现在要对这些木头进行加工,加工有以下规则: 1.你需要1分钟来准备第一根木头. 2.如果下一根木头比第一根长且重,那么不需准备时间即可加工,否则需要1分钟时间准备. 木头没有顺序,求最小时间代价.(有多组数据) 输入:第一行t:需要处理的组数,接下来有t组数据,每组第一行是n,表示木头个数,下一行是n组,每组两个数,表示第i块木头的长.重. 3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1…

POJ题目分类 | POJ题目分类 | HDU题目分类 | ZOJ题目分类 | SOJ题目分类 | HOJ题目分类 | FOJ题目分类 | 模拟题: POJ1006 POJ1008 POJ1013 POJ1016 POJ1017 POJ1169 POJ1298 POJ1326 POJ1350 POJ1363 POJ1676 POJ1786 POJ1791 POJ1835 POJ1970 POJ2317 POJ2325 POJ2390 POJ1012 POJ1082 POJ1099 POJ1114…

1257题目链接 一个序列划分子序列,每个子序列都是非增序列,问最少分成几个子序列 1800题目链接 一堆数分组,每组内数据严格递减,问最少分几组 ------------------------------------------------------------------------------------------------ 这两个题的区别在于1257数组的排列顺序不能变,而1800只是分组,顺序随意. 1257有两种解法: 一是像hdu1051那样的贪心:像筛素数那样一个序列一个…