HDOJ 1528 Card Game Cheater】的更多相关文章

版权声明:来自: 码代码的猿猿的AC之路 http://blog.csdn.net/ck_boss https://blog.csdn.net/u012797220/article/details/35236457 简单二分图匹配.... Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 1073   …
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1072    Accepted Submission(s): 564 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
题目:点击打开链接 题意:两个人纸牌游戏,牌大的人得分.牌大:2 < 3 < 4 < 5 < 6 < 7 < 8 < 9 < T < J < Q < K < A .值一样看花色, hearts (红心) > spades (黑桃) > diamond (方块) > clubs (梅花).问Eve 能得多少分.(每次得1分) 分析:将Eve的每张牌与Adam的所有牌比较,与所有比这张牌小的Adam的牌连边. 然后求最大…
http://acm.hdu.edu.cn/showproblem.php?pid=1528 Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1559    Accepted Submission(s): 820 Problem Description Adam and Eve play a card…
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1272    Accepted Submission(s): 675 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1566    Accepted Submission(s): 822 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
称号: Card Game Cheater Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 103 Accepted Submission(s): 74   Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rules…
Card Game Cheater Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 1576    Accepted Submission(s): 830 Problem Description Adam and Eve play a card game using a regular deck of 52 cards. The rule…
水题,感觉和田忌赛马差不多 #include<cstdio> #include<cstring> #include<cmath> #include<algorithm> using namespace std; struct P1 { int Num; int Hua; } Play1[]; struct P2 { int Num; int Hua; } Play2[]; bool cmp1(const P1&a,const P1&b) {…
容斥原理+状压 Card Collector Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 1940    Accepted Submission(s): 907Special Judge Problem Description In your childhood, do you crazy for collecting the bea…