问题描述:反转序列,但是有重复的元素,例如序列13111. 算法思路:如果元素有重复,那么left-mid,就不一定是有序的了,所以不能利用二分搜索,二分搜索必须是局部有序.针对有序序列的反转,如果有重复数据的话,那么必然是nums[left]=nums[mid]=nums[right],增加对这种情况的讨论即可. public boolean search(int[] nums, int target) { return binarySearch(nums, 0, nums.length -…

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise return -1. You…

public int findMin(int[] nums) { return findMin(nums, 0, nums.length - 1); } public int findMin(int[] nums, int left, int right) { int mid = (left + right)/2; if(left == right) { return nums[left]; } if(nums[left] < nums[right]) { return nums[left];…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. class Solution { public: bool search(int A[],…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这道是之前那道Search in Rotated Sorted Array 在旋转有序数组…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 我的思路: 太混乱了 不提了.注意关键区分依据 排好序的一定是从小到大的 看大神的吧: b…

原题链接,点我 该题解题参考博客 和Search in Rotated Sorted Array唯一的区别是这道题目中元素会有重复的情况出现.不过正是因为这个条件的出现,出现了比较复杂的case,甚至影响到了算法的时间复杂度.原来我们是依靠中间和边缘元素的大小关系,来判断哪一半是不受rotate影响,仍然有序的.而现在因为重复的出现,如果我们遇到中间和边缘相等的情况,我们就丢失了哪边有序的信息,因为哪边都有可能是有序的结果.假设原数组是{1,2,3,3,3,3,3},那么旋转之后有可能是{3,3…

LeetCode:Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, other…

Search in Rotated Sorted Array I Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise re…

题目来源 https://leetcode.com/problems/search-in-rotated-sorted-array-ii/ Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 和33题的区别就是http://www.cnblogs.com/li-daphne/p/5…

题目: Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 说明: 1)和1比只是有重复的数字,整体仍采用二分查找 2)方法二 : 实现:  …

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 这个题做了好长时间,到最后就这个想法... 后来看到别人真的做出来了,我于是又开始新的征程…

33. Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise…

Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…

一:Search in Sorted Array 二分查找,可有重复元素,返回target所在的位置,只需返回其中一个位置,代码中的查找范围为[low,high),左闭右开,否则容易照成死循环. 代码: class Solution { public: int search(vector<int>& nums, int target) { int numsSize = nums.size(); ,high = numsSize; while(low < high){ ; if(n…

# -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 33: Search in Rotated Sorted Arrayhttps://oj.leetcode.com/problems/search-in-rotated-sorted-array/ Suppose a sorted array is rotated at some pivot unknown to you beforehand.(i.e., 0 1 2 4 5…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4…

一天一道LeetCode 本系列文章已全部上传至我的github,地址:ZeeCoder's Github 欢迎大家关注我的新浪微博,我的新浪微博 欢迎转载,转载请注明出处 (一)题目 Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function…

description: Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i…

LeetCode 81 Search in Rotated Sorted Array II [binary search] <c++> 给出排序好的一维有重复元素的数组,随机取一个位置断开,把前半部分接到后半部分后面,得到一个新数组,在新数组中查找给定数是否存在,时间复杂度限制\(O(log_2n)\) C++ 因为有重复元素存在,nums[l] <= nums[mid]不能说明[l,mid]区间内一定是单调的,比如数组[1,2,3,1,1,1,1],但是严格小于和严格大于的情况还是可以…

LeetCode 33 Search in Rotated Sorted Array [binary search] <c++> 给出排序好的一维无重复元素的数组,随机取一个位置断开,把前半部分接到后半部分后面,得到一个新数组,在新数组中查找给定数的下标,如果没有,返回-1.时间复杂度限制\(O(log_2n)\) C++ 我的想法是先找到数组中最大值的位置.然后以此位置将数组一分为二,然后在左右两部分分别寻找target. 二分寻找最大值的时候,因为左半部分的数一定大于nums[l],所以n…

Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., [0,0,1,2,2,5,6] might become [2,5,6,0,0,1,2]). You are given a target value to search. If found in the array return true, otherwise return false. Ex…

这4个题都是针对旋转的排序数组.其中153.154是在旋转的排序数组中找最小值,33.81是在旋转的排序数组中找一个固定的值.且153和33都是没有重复数值的数组,154.81都是针对各自问题的版本1增加了有重复数值的限制条件. 153.154都需要考虑是否旋转成和原数组一样的情况,特别的,154题还需要考虑10111和11101这种特殊情况无法使用二分查找. 33.81则不用考虑这些情况. 找最小值的题主要是利用最小值小于他前一个位置的数,同时也小于后一个位置的数 153. Find Mini…

Question: Follow up for "Search in Rotated Sorted Array": What if duplicates are allowed? Would this affect the run-time complexity? How and why? Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e…

Search in Rotated Sorted Array II Follow up for "LeetCode: Search in Rotated Sorted Array 解题报告":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the arr…

Follow up for "Search in Rotated Sorted Array":What if duplicates are allowed? Would this affect the run-time complexity? How and why? Write a function to determine if a given target is in the array. 思路:本题思路和http://www.cnblogs.com/vincently/p/41…

Search in Rotated Sorted Array 系列题解 题目来源: Search in Rotated Sorted Array Search in Rotated Sorted Array II 第一版 Suppose an array sorted in ascending order is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0…

描述 Follow up for ”Search in Rotated Sorted Array”: What if duplicates are allowed?    Would this affect the run-time complexity? How and why?    Write a function to determine if a given target is in the array. 如果循环数组里有重复元素,则根据A[m]>=A[l]是无法判断出(m,l)之间是…

Search in Rotated Sorted Array Suppose a sorted array is rotated at some pivot unknown to you beforehand. (i.e., 0 1 2 4 5 6 7 might become 4 5 6 7 0 1 2). You are given a target value to search. If found in the array return its index, otherwise retu…