问题 H: Vegetable and Road again 时间限制: 1 Sec 内存限制: 128 MB 提交: 19 解决: 8 题目描述 修路的方案终于确定了.市政府要求任意两个公园之间都必须实现公路交通(并不一定有直接公路连接,间接公路相连也可以).但是考虑到经济成本,市政府希望钱花的越少越好. 你能帮助Vegetable找到给出的修路方案所需的最少花费吗? 输入 有T组测试数据. 每组包含一组N(0<n<=100)和M,N表示有N个公园,M表示这N个公园间的M条路. 接下来给出M…
Economic times these days are tough, even in Byteland. To reduce the operating costs, the government of Byteland has decided to optimize the road lighting. Till now every road was illuminated all night long, which costs 1 Bytelandian Dollar per meter…
Agri-Net Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 45050   Accepted: 18479 Description Farmer John has been elected mayor of his town! One of his campaign promises was to bring internet connectivity to all farms in the area. He nee…
Description Advanced Cargo Movement, Ltd. uses trucks of different types. Some trucks are used for vegetable delivery, other for furniture, or for bricks. The company has its own code describing each type of a truck. The code is simply a string of ex…
题目描述 如题,给出一个无向图,求出最小生成树,如果该图不连通,则输出orz 输入格式 第一行包含两个整数N.M,表示该图共有N个结点和M条无向边.(N<=5000,M<=200000) 接下来M行每行包含三个整数Xi.Yi.Zi,表示有一条长度为Zi的无向边连接结点Xi.Yi 输出格式 输出包含一个数,即最小生成树的各边的长度之和:如果该图不连通则输出orz 输入输出样例 输入 #1复制 4 5 1 2 2 1 3 2 1 4 3 2 3 4 3 4 3 输出 #1复制 7 说明/提示 时空…
POJ - 1287超级模板题 大概意思就是点的编号从1到N,会给你m条边,可能两个点之间有多条边这种情况,求最小生成树总长度? 这题就不解释了,总结就算,prim是类似dijkstra,从第一个点出发,每次走这个点没走过的最小边权值,这样不断找下去就可以找出,本质就是贪心算法 而kruskal是利用并查集,先按照边权值大小排序,然后从小的边开始往里面添加边,利用并查集判断是否在一个联通分量里面(就是是否相连)如果不相 连就建立边,从而建图,注意,节点编号如果是从1->n,那么相应初始化就应该从…
poj 1251  && hdu 1301 Sample Input 9 //n 结点数A 2 B 12 I 25B 3 C 10 H 40 I 8C 2 D 18 G 55D 1 E 44E 2 F 60 G 38F 0G 1 H 35H 1 I 353A 2 B 10 C 40B 1 C 200Sample Output 21630 prim算法 # include <iostream> # include <cstdio> # include <cstr…
http://poj.org/problem?id=1258 Description Farmer John has been elected mayor of his town! One of his campaign promises was to bring internet connectivity to all farms in the area. He needs your help, of course. Farmer John ordered a high speed conne…
Description You are assigned to design network connections between certain points in a wide area. You are given a set of points in the area, and a set of possible routes for the cables that may connect pairs of points. For each possible route between…
http://acm.hdu.edu.cn/showproblem.php?pid=1879 刚开始么看清题  以为就是n行  后来一看是n*(n-1)/2行   是输入错误  真是够够的 #include <iostream> #include <cstring> #include <algorithm> #include <queue> #include <cstdio> #include <cstdlib> #include &…