Codeforces 879C/878A - Short Program】的更多相关文章

传送门:http://codeforces.com/contest/879/problem/C 本题是一个位运算问题——位运算的等价变换. 假设位运算符“&”“|”“^”是左结合的,且优先级相同,则一个表达式:“x@a[1]@a[2]@...@a[n]”,等价于“(...((x@a[1])@a[2])...)@a[n]”.其中,“@”为位运算符“&”“|”“^”. 将表达式“x@a[1]@a[2]@...@a[n]”表示为一个简单的等价形式:“((x&a)|b)^c”,即“x&am…
原题链接:http://codeforces.com/problemset/problem/878/A 题意:给出n个位运算操作, 化简这些操作, 使化简后的操作次数不多于5步. 思路:我们可以对二进制每一位上的1, 0, 进行讨论, 如果n次操作后1 -->1, 0 --> 1, 说明这一位要用或操作(or 1) 类似的,1 -->0, 0 -->1, 说明这一位要用异或操作(xor 1)        1 -->0, 0 -->0, 说明这一位要用与操作(and 0…
A. Short Program link http://codeforces.com/contest/878/problem/A describe Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well. In the language…
题目链接:http://codeforces.com/contest/879/problem/C C. Short Program time limit per test2 seconds memory limit per test256 megabytes Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and re…
C. Short Program time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and retur…
C. Short Program time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and retur…
给你一串$n$个按顺序的位运算操作(&,|,^),形如"opt x",要求用不超过5行的位运算,按顺序操作出来和那个结果是一样的.$(n<=5e5,0<=x<1024)$ 会了之后很水.构造.. 首先确定每一位是原来是$1$会变成啥,是$0$会变成啥. 然后用位运算构造.我太菜md居然不会...... 具体如下 假设最后要或$a$,与$b$,异或$c$.初值$a=0,b=1023,c=0$.如果啥也不改输入啥还是输出啥. $0\rightarrow1,1\ri…
[链接] 我是链接,点我呀:) [题意] 给你一个n行的只和位运算有关的程序. 让你写一个不超过5行的等价程序. 使得对于每个输入,它们的输出都是一样的. [题解] 先假设x=1023,y=0; 即每位都是1和每位都是0; 然后做一下这n个操作. 得出,每一位如果是0的话输出应该是几,以及每一位是1的话输出应该是几. 会发现,用or和xor和and就能完成. [代码] #include <bits/stdc++.h> #define ll long long using namespace s…
传送门 题目大意: 输入给出一串位运算,输出一个步数小于等于5的方案,正确即可,不唯一. 题目分析: 英文题的理解真的是各种误差,从头到尾都以为解是唯一的. 根据位运算的性质可以知道: 一连串的位运算最终都可以用三个位运算代替(&|^). 那么仅需对每一位的情况进行讨论,某一位: 必须变为1 (|1) 必须变为0 (&0) 必须01颠倒(^1) 最后输出3种位运算即可(输出三种最稳妥). code #include<bits/stdc++.h> using namespace…
http://codeforces.com/contest/879/problem/C Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well. In the language, there are only three commands…
题目链接:http://codeforces.com/contest/284/problem/D 题意:给出n个数,奇数次操作x,y都加上a[x],偶数次操作y加上a[x],x减去a[x],走出了范围就结束. 问结束时的y值,如果无法结束,那么输出-1 题解:很显然可以用记忆化搜索来解决,可以设dp[i][j](i=0表示偶数次操作以j为结尾的y值是多少,i=1表示奇数次操作以j为结尾的y值是多少) 在加一个辅助的vis[i][j](i=0表示偶数次操作以j为结尾有没有取过,i=1表示奇数次操作…
题目类型:位运算 传送门:>Here< 题意:给出\(N\)个位运算操作,要求简化操作数量,使之结果不受影响(数据在1023之内) 解题思路 我们发现数字的每一位是独立的.也就是说,每一个操作可以看成是对数字的二进制的每一位进行操作.而二进制只有0或1,因此如果我们能够确定每一位有没有变,是怎么变的,就可以确定当前这一位发生了什么操作.因此,很显然我们可以把操作数量压缩成3步:&,|,^. 每一位的变化无非四种情况:对于初始状态和最终状态,不过时0->0,0->1,1-&g…
Codeforces Round #443 (Div. 2) codeforces 879 A. Borya's Diagnosis[水题] #include<cstdio> #include<cstring> #include<algorithm> using namespace std; int main(){ , s, d; scanf("%d", &n); while(n--) { scanf("%d%d", &a…
A. Short Program time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and retur…
C. Short Program Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and returns one non-negative integer as well. In the language, there are only three commands: apply a bitwise operation…
C. Short Program time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output Petya learned a new programming language CALPAS. A program in this language always takes one non-negative integer and retur…
http://codeforces.com/contest/879/ A. Borya's Diagnosis time limit per test 2 seconds memory limit per test 256 megabytes input standard input output standard output It seems that Borya is seriously sick. He is going visit n doctors to find out the e…
B - B CodeForces - 879B n people are standing in a line to play table tennis. At first, the first two players in the line play a game. Then the loser goes to the end of the line, and the winner plays with the next person from the line, and so on. The…
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http://www.cs.yale.edu/homes/aspnes/pinewiki/C%282f%29Macros.html See KernighanRitchie Appendix A12.3 for full details on macro expansion in ANSI C and http://gcc.gnu.org/onlinedocs/cpp/Macros.html for documentation on what gcc supports. The short ve…
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