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Leetcode 1021. Remove Outermost Parentheses

括号匹配想到用栈来做: class Solution: def removeOuterParentheses(self, S: str) -> str: size=len(S) if size==0: return "" i=0 strings=[] while i<size: stack=[S[i]] string=S[i] i+=1 while i<size: if S[i]=='(': stack.append(S[i]) else: stack.pop() s…

LeetCode #1021. Remove Outermost Parentheses 删除最外层的括号

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题目如下: A valid parentheses string is either empty (""), "(" + A + ")", or A + B, where A and B are valid parentheses strings, and + represents string concatenation.  For example, "", "()", "(())()"…

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A valid parentheses string is either empty (""), "(" + A + ")", or A + B, where A and B are valid parentheses strings, and +represents string concatenation.  For example, "", "()", "(())()", and …

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