[leetcode]_Merge Sorted Array】的更多相关文章

题目:合并两个有序数组A , B,将合并后的数组存到A中.假设A的空间足够装下A和B所有的元素. 思路:这道题考虑如果正向扫描两个数组,则每插入一个元素,则需移动A后的所有元素.换个角度想,既然元素个数一定,则从尾部扫描两个数组,依次放入到A的尾部,这样既不会产生大量元素的移动,也不会造成A中元素被覆盖.很顺利~ 代码: public void merge(int A[], int m, int B[], int n) { int start = m + n - 1; int i = m - 1…
LeetCode:Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST 分析:找到数组的中间数据作为根节点,小于中间数据的数组来构造作为左子树,大于中间数据的数组来构造右子树,递归解法如下 /** * Definition for binary tree * struct…
Given an array where elements are sorted in ascending order, convert it to a height balanced BST. 这道题是要将有序数组转为二叉搜索树,所谓二叉搜索树,是一种始终满足左<根<右的特性,如果将二叉搜索树按中序遍历的话,得到的就是一个有序数组了.那么反过来,我们可以得知,根节点应该是有序数组的中间点,从中间点分开为左右两个有序数组,在分别找出其中间点作为原中间点的左右两个子节点,这不就是是二分查找法的核…
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m …
我在Github上新建了一个解答Leetcode问题的Project, 大家可以参考, 目前是Java 为主,里面有leetcode上的题目,解答,还有一些基本的单元测试,方便大家起步. 题目: Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal…
原题地址:https://oj.leetcode.com/problems/merge-sorted-array/ 题意:Given two sorted integer arrays A and B, merge B into A as one sorted array. 解题思路:归并排序的归并这一步的实现,原理很多地方都有.使用一个tmp临时数组进行归并. 代码: class Solution: # @param A a list of integers # @param m an int…
LeetCode上牵扯到Rotated Sorted Array问题一共有四题,主要是求旋转数组的固定值或者最小值,都是考察二分查找的相关知识.在做二分查找有关的题目时,需要特别注重边界条件和跳出条件.在做题的过程中,不妨多设几个测试案例,自己判断一下. 下面是这四题的具体解答. 33.Search in Rotated Sorted Array 在求旋转数组中查找固定值,数组中每个数唯一出现.返回查找索引. class Solution: def search(self, nums: List…
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note:You may assume that A has enough space (size that is greater or equal to m + n) to hold additional elements from B. The number of elements initialized in A and B are m …
Convert Sorted Array to Binary Search Tree Given an array where elements are sorted in ascending order, convert it to a height balanced BST.SOLUTION 1:使用递归解决. base case: 当索引值超过时,返回null. 递归主体:构造根节点,调用递归构造左右子树.并将左右子树挂在根节点上. 返回值:返回构造的根节点. GITHUB: https:…
Given two sorted integer arrays A and B, merge B into A as one sorted array. Note: You may assume that A has enough space to hold additional elements from B. The number of elements initialized in A and B are m and n respectively. 题意:给定两已排好的数组,将B合并到A中…